Lightning bolt charge physics problem

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SUMMARY

The discussion revolves around calculating the charge deposited on an airplane struck by a lightning bolt carrying 30,000 A for 50 microseconds. The charge from the lightning bolt is calculated using the formula q = it, resulting in 1.5 C. The user attempts to find the charge on the airplane at 20,000 feet but initially misapplies the integration concept. The correct approach involves using the same formula, confirming that the charge deposited on the airplane is also 1 C, derived from the current and time parameters provided.

PREREQUISITES
  • Understanding of electric charge and current (Coulomb's Law)
  • Familiarity with calculus, specifically integration
  • Knowledge of basic physics concepts related to electricity
  • Ability to apply formulas for charge calculation (q = it)
NEXT STEPS
  • Review the principles of electric charge and current in physics
  • Study integration techniques and their applications in physics problems
  • Learn about the effects of lightning strikes on aircraft
  • Explore advanced topics in electromagnetism related to charge transfer
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Students studying physics, particularly those focusing on electromagnetism, as well as educators seeking to clarify concepts related to electric charge and current calculations.

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Homework Statement


A lightning bolt carrying 30,000 A lasts for 50 microseconds. If the lightning strikes an airplane flying at 20,000 ft, what is the charge deposited on the plane?


Homework Equations


q(t) = \int i(x)dx


The Attempt at a Solution


So, using the equation above I found the charge of the lightning bolt to be 30,000A * 50 x 10^-6

q(t) = 1.5 c

Then to find charge of the airplane
q(t) = \int 20,000dx from 0 to 50 microseconds

q(t) = 20,000x
q(t) = 20,000 (50 x 10^-6) = 1

I'm a bit rusty on my physics as you can see. Maybe someone can direct me to a more precise approach. Thank you
 
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x is not time i guess
 


i could find the charge of the lightning bolt by q = it given i = 30,000 A and t = 50 x 10^-6 s

q = 30,000A) * (50 x 10^-6 s) = 1.5 C

but how can I find the charge deposited onto the plane at 20,000 feet?
 

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