Lim {x -> 1} x / (x - 1) = infty

[farleyknight]

Homework Statement

Prove that \lim_{x \to 1} \frac{x}{x - 1} = \infty

Homework Equations

The Attempt at a Solution

First 0 < |x - 1| < \delta implies \frac{x}{x - 1} > N, \forall N

Because the reals are dense, we can choose an n > 0 such that \frac{x}{x - 1} > \frac{n}{x - 1} > N

then \frac{n}{x - 1} > N
\frac{1}{x - 1} > \frac{N}{n}
x - 1 < \frac{n}{N}

So choose \delta = \frac{n}{N}

and 0 < |x - 1| < \delta holds

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My first question is of course, is this proof correct. Secondly, if it's not, my other question is, is choosing an n as I've done above, a legal operation? Could it be changed to make it a legal operation?

Thanks,
- Rob

 

[Dick]

No. Not so good. For one thing the limit is only infinity if x>1 (x approaching 1 from the right). If x approaches from the left it's negative infinity. Start by taking your condition that x/(x-1)>N. Change that into an inequality condition for x. Can you deduce from that how to pick a delta?