Limit and Derivative Problems with Infinity: Can Someone Explain?

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The discussion focuses on solving various limit problems as n approaches infinity, including expressions involving fractions and trigonometric functions. Participants are asked to explain the reasoning behind the limits, particularly for complex expressions like lim as x approaches 0+ of {[1+(x/2)]^(2/x)}^(1/2) equating to e^(1/2). One response highlights that simplifying the first limit reveals that the denominator approaches zero, leading to an infinite result. The conversation emphasizes the need for clear explanations of each step in the limit calculations. Overall, the thread seeks clarity on the application of limits and derivatives involving infinity.
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Would some one please show me how to do these problems below.
Thanks so much
1) lim of n as n approaches to infinity 1/[1-(n/(n-1))]
2) lim of n as n approaches to infinity (n-1)/[n-(1/n)]
3) lim of n as n approaches to infinity n * sin (1/n)
4) lim of n as n approaches to infinity (1/n)-(1/(n+1))

****Would u please also explain this to me:
Y does lim of x as x approaches to 0+ {[1+(x/2)]^(2/x)}^(1/2) = e^(1/2)?
I don't understand y they r equal??
 
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Would some one please show me how to do these problems below.
Thanks so much
1) lim of n as n approaches to infinity 1/[1-(n/(n-1))]
2) lim of n as n approaches to infinity (n-1)/[n-(1/n)]
3) lim of n as n approaches to infinity n * sin (1/n)
4) lim of n as n approaches to infinity (1/n)-(1/(n+1))

****Would u please also explain this to me:
Y does lim of x as x approaches to 0+ {[1+(x/2)]^(2/x)}^(1/2) = e^(1/2)?
I don't understand y they r equal??
 
1) lim of n as n approaches to infinity 1/[1-(n/(n-1))]

look at the n/n-1 part first.

Times both the top and the bottom by 1/n. That gives you 1/(1-1/n) The 1/n term goes to zero, so this part = 1

that leaves you with lim as x goes to 1 of 1/1-x, which is means the denominator goes to zero, so the equation goes to infinity.

Why don't you post what part you are stuck on with the rest?
 
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