Limit of a sequence in a closed interval is in that interval

missavvy
Messages
73
Reaction score
0

Homework Statement


Suppose [a,b] is a closed interval (on R), and {xn}n>=1 is a sequence such that
a) xn belongs to [a,b]
b) lim as n--> infinity xn = x exists
prove x belongs to [a,b]


Homework Equations





The Attempt at a Solution



Well since any sequence is bounded, then obviously the limit has to be within the bounds.

Not sure where to begin though. I'm thinking of using the definition of a limit..? For all k>0, there exists a natural # N such that for all n>=N, |x-xn|<k
Or that this is Cauchy since it is bounded ?

Just not exactly how to go about showing that x is in that interval!
 
Physics news on Phys.org
I would do a proof by contradiction. Assume x is outside of [a,b]. Isn't it pretty easy to derive a contradiction?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top