Is it correct that [itex]|\sin x|=-\sin x[/itex] as [itex]x\rightarrow 0-[/itex]?(adsbygoogle = window.adsbygoogle || []).push({});

It's clear for a function like [itex]y=x[/itex], but I ask the question since the sine oscillates from positive to negative values, so for different x's the abs. value is either pos. or neg. Or do I only need to consider values of x that are between -pi and 0?

I know the limit is zero, I just need to know how to write the intermediate step of getting rid of the abs. value sign.

- Kamataat

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Limit of absolute value

**Physics Forums | Science Articles, Homework Help, Discussion**