Limit of an exponent when it goes to infinity

RyozKidz
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how this thing works ?

integration of e to the power of (-x) from 0 to infinity

sorry , not good in using the symbols ..^.^ ~
 
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Hi
Do you know what the primitive of e^{-x} is ?
 
First integrate it, then you get [-e-x] from 0 to infinity.

The key is to find the limit as x approaches infinity of (-e-x).

(Hint: Put in a very large negative value for x and see what you get.)
 
sorry ..~ i missed out the negative ..~
now i know already ..~ tq tq ...
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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