Limit of serverable variables,

  • Thread starter Thread starter th3plan
  • Start date Start date
  • Tags Tags
    Limit Variables
th3plan
Messages
93
Reaction score
0

Homework Statement


(x,y)---> (0,0)
x²+y²/√(x²+y²+1) - 1

the -1 isn't in the square root, so people know




The Attempt at a Solution


i let y=o and got 2, and y=x² and x=y² and got 2, so how can i be sure this limit is 2, what other method must i try to be sure ?
 
Last edited:
Physics news on Phys.org
What exactly is the limit going to? And your problem is very hard to interpret ... might want to re-type that with proper parenthesis.

let x=y
 
Last edited:
th3plan said:

Homework Statement


(x,y)---> (0,0)
x²+y²/√(x²+y²+1) - 1

the -1 isn't in the square root, so people know
But is it in the denominator? Is this (x^2+ y^2)/(\sqrt{x^2+ y^2})+ 1 or (x^2+ y^2)/(\sqrt{x^2+ y^2}+ 1) ?



The Attempt at a Solution


i let y=o and got 2, and y=x² and x=y² and got 2, so how can i be sure this limit is 2, what other method must i try to be sure ?[/QUOTE]
One way to check is to change to polar coordinates. Since only r measures "distance to (0,0), if the limit, as r goes to 0, does not depend on \theta, that is the limit.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top