Limit Problem - Electric field strength of an infinite line of charge

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SUMMARY

The limit of the electric field strength of an infinite line of charge is determined by the equation lim (L→∞) (K|Q|)/(r√(r²+(L/2)²)). The solution simplifies to (K|Q|)/(rL/2) as L approaches infinity. Key steps include factoring out L² from the square root, leading to the conclusion that as L increases, the term r/L approaches zero. This analysis is crucial for understanding the behavior of electric fields in theoretical physics.

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  • Understanding of electric fields and charge distributions
  • Familiarity with limits in calculus
  • Knowledge of algebraic manipulation and square roots
  • Basic concepts of physics related to electromagnetism
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  • Study the concept of limits in calculus, focusing on infinite limits
  • Explore electric field calculations for different charge distributions
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JJBladester
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Limit Problem --- Electric field strength of an infinite line of charge

Homework Statement



What is the limit of the following equation?

Homework Equations



[tex]\stackrel{lim}{L\rightarrow\infty} \frac{K|Q|}{r\sqrt{r^{2}+(L/2)^{2}}}[/tex]

The Attempt at a Solution



The book gives an answer of [tex]\frac{K|Q|}{rL/2}[/tex] but it doesn't explain the intermediate steps.

K is a constant, Q represents charge, L represents length, and r represents distance from a wire to a point in space. The whole exercise is to see what happens to the electric field strength of the wire if its length is allowed to grow infinitely.
 
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Factor the L^2 out of the expression in the square root. So sqrt(r^2+(L/2)^2)=sqrt(L^2(r^2/L^2+1/4)=sqrt(L^2)*sqrt((r/L)^2+1/4)=L*sqrt((r/L)^2+1/4). Now as L->infinity, r/L goes to zero.
 


Dick,

Thanks for your response. The first sentence you made helped me get through it!

Factor the L^2 out of the expression in the square root... I guess the more problems I do, the more my math intuition will increase. On that note, I found a site www.betterexplained.com that has really helped me conceptualize things like "what is a limit" without a cheesy explanation like "the area under the curve". Check it out :)
 

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