Limit problem simplify the root

StrSpeed
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Homework Statement


[/B]
I feel like I'm missing some theorem which is preventing me from finalizing this problem! It's been driving me nuts I feel like I'm missing something super basic!

Ultimately they've given the solution, g/8, so I know this is how I should try to get the equation to look algebraically. But, no matter how I manipulate it I can't get it to reduce.

I feel like this has to do with √x2 = |x| Which then depending on your value of x will give x, or -x. However, I can't simplify the root into a way which will let me make this jump.
upload_2015-6-5_12-25-51.png


Homework Equations


https://www.desmos.com/calculator/hf8poewlvb

The Attempt at a Solution


https://www.desmos.com/calculator/hf8poewlvb
(link to all my reductions)
 
Last edited:
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Try multiplying numerator and denominator by$$
c\sqrt{\left(\frac{c^2}{g^2}+\frac 1 4\right)}+\frac{c^2}{g}$$
 
The conjugate! How could I forget that.. Thank you! Now I have:

PS. g is not squared I wrote it down wrong.
VhM1czk.jpg


Let me see what more I can do.
 
Alternatively: You can take a common factor out of the expression under the square root to obtain <br /> h(c) = A\sqrt{1 + x} - \frac{c^2}{g} where x &lt; 1 for sufficiently large c. Hence you may expand the root as a binomial series, <br /> (1 + x)^{\alpha} = 1 + \alpha x + \frac{\alpha(\alpha - 1)}{2!}x^2 + \dots
 
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Thanks for both of your help! Still working on it, sadly.. I pulled out a C so I'm left with:

https://www.physicsforums.com/file:///C:/Users/Steven/Downloads/CodeCogsEqn.gif
7ScJ3py.gif


Im not entirely sure what I could pull out of the root.
 
Last edited by a moderator:
StrSpeed said:
Thanks for both of your help! Still working on it, sadly.. I pulled out a C so I'm left with:

https://www.physicsforums.com/file:///C:/Users/Steven/Downloads/CodeCogsEqn.gif
7ScJ3py.gif


Im not entirely sure what I could pull out of the root.
Factor out the c you'll have 1/4 * (lim c ->0 1/(sqrt(1/g^2 + 1/4c) + 1/g) and don't forget that 1/4c goes to 0 whenever c -> 0, good luck
 
Last edited by a moderator:
StrSpeed said:
The conjugate! How could I forget that.. Thank you! Now I have:

PS. g is not squared I wrote it down wrong.
VhM1czk.jpg


Let me see what more I can do.
That's good.

##\displaystyle \ \frac14\lim_{c\to\infty}\left(\frac{c^2}{\displaystyle c\sqrt{\left(\frac{c^2}{g^2}+\frac 1 4\right)}+\frac{c^2}{g}}\right)\ ##

One way to deal with rational expressions where some factor →∞ : divide the numerator and denominator by the highest power of that factor.

Divide by c2 in the numerator & denominator.
 
I got it! You guys rock thank you so much! Once I got down to that last x Term I realized that a constant/infinity = 0!

Here is my work through!
od4ZL7X.jpg
 
You should drop the limit sign from the second last row.
 
  • #10
StrSpeed said:
I got it! You guys rock thank you so much! Once I got down to that last x Term I realized that a constant/infinity = 0!

Here is my work through!
upload_2015-6-5_22-57-10.png
At the point highlighted above, simply take the limit and simplify.
 

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