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Beamsbox
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This is an assignment problem I have. Can't seem to figure it out. It has two parts, one to prove that the function approaches 0 where y=mx and and one where the function approaches 0 from y=kx2...
f(x,y) = (x3y)/(2x6+y2)
I've attempted both parts and get stuck on what seems like the same issue. Basically I've substituted y=mx for y. Giving:
Please assume that lim (x,mx)→(0,0) is at the beginning of these workings.
lim f(x,mx) = x3(mx)/(2x6+(mx)2)
lim f(x,mx) = mx4/[(x2(2x4+m2)]
lim f(x,mx) = mx2/(2x4+m2)
I suppose I could try L'Hopital at this point, but it doesn't seem to help I think the 3rd derivative leaves you with 0/0.
Could I get some direction, please?
Thanks prior!
f(x,y) = (x3y)/(2x6+y2)
I've attempted both parts and get stuck on what seems like the same issue. Basically I've substituted y=mx for y. Giving:
Please assume that lim (x,mx)→(0,0) is at the beginning of these workings.
lim f(x,mx) = x3(mx)/(2x6+(mx)2)
lim f(x,mx) = mx4/[(x2(2x4+m2)]
lim f(x,mx) = mx2/(2x4+m2)
I suppose I could try L'Hopital at this point, but it doesn't seem to help I think the 3rd derivative leaves you with 0/0.
Could I get some direction, please?
Thanks prior!
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