Solving for m: Find Limit of [e^(mx^2)-cos(8x)]/x^2 = 64

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SUMMARY

The limit of the expression [e^(mx^2) - cos(8x)]/x^2 as x approaches 0 is analyzed to determine the value of m that satisfies the equation equating the limit to 64. The initial application of L'Hôpital's Rule was performed twice, leading to an incorrect conclusion that the limit is 32. The correct approach involves re-evaluating the second derivative of the numerator, specifically the term e^(mx^2), which reveals that the correct value for m is 32.

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sparkle123
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Find m:
lim([e^(mx^2)-cos(8x)]/x^2)=64 where x-->0

I used l'hopital's twice and got
lim [2m^2x^2e^(mx^2)+32cos(8x)]
=32

which means the limit is never 64.
the right answer is m=32 though. Where am I wrong?
 
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Redo the second derivative of your numerator. Especially the first term.
 
Got it! Thanks :)
 

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