B Line Equations: Rearranging Ax + By + C = 0 to y=mx+b

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The discussion focuses on rearranging the general line equation Ax + By + C = 0 into the slope-intercept form y = mx + b. Participants confirm that this rearrangement is possible by isolating y, resulting in y = (-A/B)x + (-C/B), provided that B is not zero. It is noted that vertical lines, such as x = 2, cannot be expressed in slope-intercept form due to their undefined slope. The conversation emphasizes that all allowed operations can be performed on equations to achieve the desired format, except in cases where B equals zero. Overall, the rearrangement is valid for non-vertical lines.
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Say a line equation is expressed with the General equation of Ax + By + C = 0; can one just simply rearrage this into the form of y= mx + b?
 
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What ways of rearranging Ax + By + C = 0 into the form y= mx + b have you tried ?
 
Nidum said:
What ways of rearranging Ax + By + C = 0 into the form y= mx + b have you tried ?
I just made y the subject so that
Y= (-a/-b)x + (-c/-b); this may not be correct, I've just done it now
 
You can simplify the expression.
It doesn't work if b=0.

You can always perform all allowed operations on equations.
 
Einstein's Cat said:
Say a line equation is expressed with the General equation of Ax + By + C = 0; can one just simply rearrage this into the form of y= mx + b?
Vertical lines such as x = 2 are special cases of the general equation (A = 1, B = 0, C = -2), but can't be written in the slope-intercept form, since the slope is undefined. Any other line that isn't vertical can be written in either equation form.
 
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