Line integral over the perimiter of a hexagram

  • Thread starter jjheat
  • Start date
  • #1
3
0
Solved

Thanks
 
Last edited:

Answers and Replies

  • #2
Dick
Science Advisor
Homework Helper
26,260
619
You just want to multiply 4 time the area of the figure, right? Sure, the area is 12 times the area of a single triangle. What's the area of an equilateral triangle with side 1? That's a trig problem, not a calc problem.
 
  • #3
3
0
Thanks
 
Last edited:
  • #4
Dick
Science Advisor
Homework Helper
26,260
619
Just to clarify:

So you're saying that we don't even need the integral because you can pull the 4 out and if you just integrate (1), you get 1/2?

Then I multiply by 12 so the answer is 4*12*(1/2)=24?
That's ok up until you integrated 1 over the triangle and got 1/2. The area of a triangle with side length 1 isn't 1/2, is it?
 
  • #5
3
0
Thanks again!
 
Last edited:
  • #6
1
0
I have the same problem but I cannot see the entire thread
 
  • #7
Dick
Science Advisor
Homework Helper
26,260
619
I have the same problem but I cannot see the entire thread
jjheat deleted half the thread. That's not considered very polite or sporting. If everyone did it, it would make searching the old archives pretty useless. Feel free to start your own thread. The idea is to use Green's theorem to convert the hard contour integral into an easy surface integral. Try that.
 

Related Threads on Line integral over the perimiter of a hexagram

Replies
1
Views
4K
  • Last Post
Replies
6
Views
7K
  • Last Post
Replies
5
Views
904
  • Last Post
Replies
7
Views
675
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
0
Views
1K
Replies
1
Views
695
Replies
2
Views
1K
  • Last Post
Replies
3
Views
486
Top