Line Integral - Vector Calculus

Click For Summary
SUMMARY

The discussion focuses on calculating the line integral of the vector field f(x,y) = (x² - 2xy)î + (y² - 2xy)j along the parabola defined by y = x², between the points (-1,1) and (1,1). The correct approach involves substituting y = x² into the integral and ensuring that dy is expressed in terms of x. The final result of the integral is confirmed to be -14/15. Participants emphasize the importance of correctly setting up the integral and converting dy appropriately.

PREREQUISITES
  • Understanding of vector calculus concepts, specifically line integrals.
  • Familiarity with parametric equations, particularly for curves like parabolas.
  • Knowledge of integration techniques in multivariable calculus.
  • Ability to manipulate and substitute variables in integrals.
NEXT STEPS
  • Study the method of calculating line integrals in vector fields.
  • Learn about parametric representations of curves and their applications in integration.
  • Explore the concept of converting differentials, such as dy in terms of dx.
  • Practice solving line integrals with various vector fields and paths.
USEFUL FOR

Students and professionals in mathematics, particularly those studying vector calculus, as well as educators looking to enhance their understanding of line integrals and their applications.

cristina89
Messages
29
Reaction score
0

Homework Statement


Calculate the line integral:
f(x,y) = (x² - 2xy)î + (y² - 2xy)j, between the points (-1,1) and (1,1) along the parabola y = x².
(resp: -14/15)


The attempt at a solution
I thought something like this: substitue y = x², and then integrate de f(x,y). And then evaluate from -1 to 1, but it didn't work, obviously. How should I start solving this? I think I didn't get the concept about this kind of exercise...
 
Physics news on Phys.org
If it didn't work then you must have made an error in the integrall. What, exactly, did you do?

The integral of this will be \int (x^2 - 2xy)dx+ (y^2- 2xy)dy[//itex]. Did you remember to put dy in terms of x also?
 
HallsofIvy said:
If it didn't work then you must have made an error in the integrall. What, exactly, did you do?

The integral of this will be \int (x^2 - 2xy)dx+ (y^2- 2xy)dy[//itex]. Did you remember to put dy in terms of x also?
<br /> <br /> Ahh, that&#039;s exactly what I was forgetting! Thank you!
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
Replies
20
Views
2K
Replies
12
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
12
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K