Linear algebra - basis of subspace

In summary, a basis of the subspace of R4 consisting of vectors perpendicular to (1, 0, 5, 2) and (0, 1, 5, 5) can be found using the Gram-Schmidt process or by setting up equations using the dot product with a general vector in R4.
  • #1
cdub2
5
0

Homework Statement



Find a basis of the subspace of R4 that consists of all vectors perpendicular to both

(1
0
5
2)

and

(0
1
5
5)

^ those are vectors.


Homework Equations





The Attempt at a Solution



I understand that a basis needs to be linearly independent and that it needs to span the vector space, but I am thrown off by the fact that the basis needs to consist of vectors perpendicular to those vectors above.
 
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  • #2
do you know about orthogonal projections? or perhaps the gram-schmidt process? seems like the perfect time to use it. don't know if wikipedia links are allowed to be posted here, but here is a link to gram schmidt in case you haven't read about it. the process itself might seem tedious but is very simple.

http://en.wikipedia.org/wiki/Gram–Schmidt_process

hope this helps.

cj.
 
  • #3
Another approach is to Let u = (u1, u2, u3, u4) be a vector in R4.

Since u is perpendicular to both of your given vectors, the dot product of u with each of the given vectors should be 0. That will give you two equations in four unknowns. These equations can be used to find a basis for your subspace.
 
Last edited:
  • #4
thanks! i got it :)
 

1. What is a basis in linear algebra?

A basis in linear algebra is a set of linearly independent vectors that span a subspace. This means that any vector in the subspace can be written as a linear combination of the basis vectors. The number of basis vectors is equal to the dimension of the subspace.

2. How do you determine if a set of vectors forms a basis?

To determine if a set of vectors forms a basis, you can use the rank-nullity theorem. This theorem states that the dimension of a subspace is equal to the sum of the rank (number of linearly independent columns) and the nullity (number of free variables) of the matrix formed by the vectors. If the rank of the matrix is equal to the number of vectors and there are no free variables, then the set of vectors forms a basis.

3. Can a subspace have more than one basis?

Yes, a subspace can have multiple bases. This is because there are usually infinitely many ways to choose a set of linearly independent vectors that span a given subspace. However, all bases for a given subspace will have the same number of vectors (equal to the dimension of the subspace).

4. How do you find the coordinates of a vector with respect to a basis?

To find the coordinates of a vector with respect to a basis, you can use the change of basis formula. This involves finding the inverse of the matrix formed by the basis vectors and multiplying it by the vector. The resulting vector will have the coordinates of the original vector with respect to the basis.

5. Can you have a basis for a subspace that is not a set of orthogonal vectors?

Yes, it is possible to have a basis for a subspace that is not a set of orthogonal vectors. While orthogonal bases can be useful in certain applications, they are not necessary for a basis to be valid. As long as the basis vectors are linearly independent and span the subspace, they can form a basis.

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