Linear Algebra: Find a formula for a matrix M to any power

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SUMMARY

The discussion focuses on finding a formula for raising a matrix M to any power using its eigenvalues and eigenvectors. The matrix A is represented as A = SDS-1, where S is the matrix of eigenvectors and D is the diagonal matrix of eigenvalues. The eigenvalue λ = 8 has a multiplicity of 2, leading to the need for two eigenvectors to construct the S and D matrices. The Jordan canonical form is utilized to express P(A) in terms of the eigenvalues and fixed matrices Ei,k, ultimately deriving the formula Mn = E1 8n + E2 n 8n-1.

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  • Understanding of eigenvalues and eigenvectors
  • Familiarity with Jordan canonical form
  • Knowledge of matrix diagonalization techniques
  • Proficiency in polynomial functions and their properties
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  • Study the process of diagonalizing matrices using eigenvalues and eigenvectors
  • Learn about Jordan canonical form and its applications in linear algebra
  • Explore polynomial functions and their role in matrix exponentiation
  • Investigate the relationship between matrix powers and eigenvalues in greater depth
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Students and educators in linear algebra, mathematicians working with matrix theory, and anyone involved in computational mathematics or applied mathematics requiring matrix exponentiation techniques.

Neutrinogun
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Homework Statement


sCWkyXV.png



Homework Equations


A = SDS-1

Under some specific conditions,

An=SDnS-1


The Attempt at a Solution


det(A-λI) = 0
(16-λ)(-λ) - (-64)(1) = 0
λ2 - 16λ + 64 = 0

λ = 8 Multiplicity 2.

This is as far as I got because you need 2 eigenvalues to get 2 eigenvectors to create the S/D matrices. Is there another way to solve this, because this is the only way I learned. Also there has to be an answer for this because it is on webwork with fill in the blank answers.
 
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Neutrinogun said:

Homework Statement


sCWkyXV.png



Homework Equations


A = SDS-1

Under some specific conditions,

An=SDnS-1


The Attempt at a Solution


det(A-λI) = 0
(16-λ)(-λ) - (-64)(1) = 0
λ2 - 16λ + 64 = 0

λ = 8 Multiplicity 2.

This is as far as I got because you need 2 eigenvalues to get 2 eigenvectors to create the S/D matrices. Is there another way to solve this, because this is the only way I learned. Also there has to be an answer for this because it is on webwork with fill in the blank answers.

For an ##n \times n## matrix ##A##, if ##r_1, r_2, \ldots, r_p## are the distinct eigenvalues of multiplicities ##m_1, m_2, \ldots, m_p##, it follows from the Jordan canonical form that there are matrices ##E_{i,k_i}, i = 1, \ldots, p, k_i = 1, \ldots, m_i## such that
P(A) = \sum_{i=1}^p [E_{i1} P(r_i) + E_{i2} P'(r_i) + \cdots + E_{i,m_i} P^{(m_i-1)}(r_i) ]
The matrices ##E_{ik}## are fixed, and are the same for all functions ##P##.

In your case, ##P(M) = E_1 P(8) + E_2 P'(8)##, where the matrices ##E_1, E_2## are the same for any polynomial ##P## (and, in fact, for any analytic function ##f(M)##). You can get them from two known values ##P(M)##, such as for ##P(x) = 1 \Longrightarrow P(M) = I## (the identity matrix) and ##P(x) = x \Longrightarrow P(M) = M##. For ##P(x) = 1, P'(x) = 0## we get ##I = E_1 + 0 E_2## and for ##P(x) = x, P'(x) = 1## we get ##M = 8 E_1 + 1 E_2##. You can solve for ##E_1, E_2##, then get ##M^n = E_1 8^n + E_2\, n 8^{n-1}##.
 
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