Linear algebra-how do I know if something is invertible?

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Homework Help Overview

The discussion revolves around determining the invertibility of a linear transformation, specifically a reflection about the line y = x/3 in R^2. Participants explore concepts related to linear algebra and matrix representation.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the invertibility of a transformation and its matrix representation. Questions arise about the vertical line test and its applicability to transformations, as well as the geometric interpretation of reflections.

Discussion Status

There is ongoing exploration of the properties of reflections and their invertibility. Some participants suggest that reflections are their own inverses, while others question the relevance of the vertical line test in this context. No consensus has been reached, but various perspectives are being examined.

Contextual Notes

Participants reference specific geometric and algebraic concepts, such as the vertical and horizontal line tests, and the nature of reflections in linear transformations. There may be assumptions about familiarity with matrix representations and linear transformations that are not explicitly stated.

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Linear algebra--how do I know if something is invertible?

Say I have a "reflection about the line y = x/3 in R^2," how do I know if the function or "T" is invertible?

Thank you.
 
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T is inv if its matrix is invertible, I think reflecting about y = x/3 function/T is invertible .

just use vertical/horizontal line test for functions
 
Well you could first find out what the matrix representation of this linear transformation is. Are you familiar with these terms?
 
yes, but how does the vertical line test work?
 
I don't think it would work on transformations >>

for functions draw a vertical line, if it passes through the function twice then that means your function is not an actual function

and for inverse, draw horizontal line ...

something really simple stupid that I never used
 
Well there is an invertible transformation for any reflection across a line through the origin.
 
Geometrically, if you reflect a second time across the same line, you are right back where you started. Any reflection is its own inverse.
 

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