Linear Algebra: How to represent this transformation as a matrix?

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SUMMARY

The discussion focuses on representing a linear transformation T defined on the vector space V = R_{2x2} as a matrix. The transformation is given by T(\begin{bmatrix}a_{11}&a_{12}\\a_{21}&a_{22} \end{bmatrix}) = \begin{bmatrix}-2a_{11}-a_{12}&a_{11}\\a_{21}&2a_{22} \end{bmatrix}. The correct matrix representation is \begin{bmatrix}-2&-1&0&0\\1&0&0&0\\0&0&1&0\\0&0&0&2 \end{bmatrix}, which leads to eigenvalues {1, -1, 2}. The confusion arises from the calculation of the spectrum and the characteristic polynomial, emphasizing the need for clarity in identifying corresponding basis vectors.

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Homework Statement



Find the spectrum of the given linear operator T on V and find an eigenvector of T corresponding to each eigenvalue.

<br /> <br /> V = R_{2x2}, T (\begin{bmatrix}a_{11}&amp;a_{12}\\a_{21}&amp;a_{22} \end{bmatrix}) = \begin{bmatrix}-2a_{11}-a_{12}&amp;a_{11}\\a_{21}&amp;2a_{22} \end{bmatrix}<br /> <br />

Homework Equations


The Attempt at a Solution



I'm confused about how to write the columns and rows of the transformation matrix.. do I do this:

\begin{bmatrix}-2&amp;-1&amp;0&amp;0\\1&amp;0&amp;0&amp;0\\0&amp;0&amp;1&amp;0\\0&amp;0&amp;0&amp;2 \end{bmatrix} <br /> <br /> <br />

Or the transposed? Or something else?

When I tried to get the spectrum (eigenvalues?) of this matrix I get {1, 2, -2} but the answer is {1,-1,2}, which doesn't work with the characteristic polynomial..
 
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That's one way to write the matrix. Though to be absolutely clear you should say which columns correspond to which basis vector. But I get eigenvalues {1,-1,2} for your matrix. Maybe just check your eigenvalue calculation.
 

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