Linear Algebra - subspaces of f in C[-1,1]

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The discussion revolves around determining if the set of functions in C[-1,1] that satisfy f(-1)=0 and f(1)=0 forms a subspace. Participants emphasize the importance of showing that if f(x) and g(x) belong to this set, then their sum f(x)+g(x) and scalar multiples c*f(x) must also belong to the set. There is a clarification that polynomials are not necessary for this proof, as the focus should be on continuous functions that meet the endpoint conditions. The conversation highlights the realization that any continuous functions satisfying the conditions can serve as examples. Ultimately, the key takeaway is that understanding the properties of continuous functions is sufficient to prove the subspace criteria.
Roni1985
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Homework Statement


Determine whether the following are subspaces of C[-1,1]:

d) The set of functions f in C[-1,1] such that f(-1)=0 AND f(1)=0

Homework Equations


The Attempt at a Solution



I did the question with 'OR', but I don't think I can find the functions.

I am not sure I can use x2 here ...

say f2(x)=f1(x)=x2-1 will give me 0 when x=-1 or x=1
 
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C[-1,1] doesn't have anything to with polynomials. You have to show if f(x) and g(x) satisfy your condition then so does f(x)+g(x) and c*f(x). Forget the polynomials.
 
Dick said:
C[-1,1] doesn't have anything to with polynomials. You have to show if f(x) and g(x) satisfy your condition then so does f(x)+g(x) and c*f(x). Forget the polynomials.
I just solved a similar question but with 'OR' instead of 'AND'.

I actually compared my answer with this file:
http://www.math.ohio-state.edu/~chou/Site/Homework_(571)_files/Practice_Final_solution.pdf

they used the first polynomial to get the answer.

How would you suggest solving this one ?
I am kind of lost right here...
 
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You can use a polynomial to provide give a counterexample in the OR case. Because it's false and the polynomials are contained in C[-1,1]. You can't prove the case of AND just using polynomials because it is true. I already told you. Just show f(x) and g(x) vanish at both endpoints that if f(x)+g(x) and c*f(x) also have that property.
 
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Dick said:
You can use a polynomial to provide give a counterexample in the OR case. Because it's false and the polynomials are contained in C[-1,1]. You can't prove the case of AND just using polynomials because it is true.

Ohh, I see...

Dick said:
Just show f(x) and g(x) vanish at both endpoints that f(x)+g(x) and c*f(x) also have that property.

But, what are my f(x) and g(x) ?
If I can't use the polynomials, what can I use ?
are the simply the 0 functions ?
f(x)=0=g(x)
?
 
Roni1985 said:
Ohh, I see...
But, what are my f(x) and g(x) ?
If I can't use the polynomials, what can I use ?
are the simply the 0 functions ?
f(x)=0=g(x)
?

f(x) and g(x) are just continuous functions on [-1,1]. All you know about them is that f(-1)=f(1)=0 and g(-1)=g(1)=0, since they are in the set that you are supposed to prove is a subspace. That's all you need to know. Isn't that enough?
 
Dick said:
f(x) and g(x) are just continuous functions on [-1,1]. All you know about them is that f(-1)=f(1)=0 and g(-1)=g(1)=0, since they are in the set that you are supposed to prove is a subspace. That's all you need to know. Isn't that enough?
OMG, you are so right ...

now it's crystal clear :\

thanks very much...
 

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