Linear Collisions: Find Max Compression of Spring

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The discussion revolves around calculating the maximum compression of a spring during a collision between two blocks of different masses moving at different speeds. The initial momentum and kinetic energy of both blocks are calculated, with the first block having a momentum of 20 kg·m/s and kinetic energy of 100 J, while the second block has a momentum of 15 kg·m/s and kinetic energy of 22.5 J. The conversation suggests using the center of mass approach and conservation laws to analyze the collision dynamics. Participants emphasize the importance of understanding the relationship between velocities at maximum spring compression. The overall goal is to find the maximum compression of the spring using the principles of momentum and energy conservation.
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Homework Statement


A block of mass m1=2.0 kg slides along a frictionless table with a speed of 10 m/s. Directly in front of it, and moving in the same direction, is a block of mass m2=5.0 kg moving at 3 m/s. A massless spring with spring constant k = 1120 nt/m is attached to the backside of m2 as shown in the diagram below. When the blocks collide, what is the maximum compression of the spring? Assume that the spring doesn't bend and always obeys Hooke's law.

Homework Equations


I'm not really sure how to do this but:
p=mv
KE=1/2mv^2
KE=1/2kx^2

The Attempt at a Solution


p1=20kgm/s p2=15kgm/s
KE1=100J KE2=22.5J
I have no idea what to do now though, or even if I need any of that information
 
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A kinetic energy cannot have units of Watts.
You could consider the center of mass system - before the collision and at the point of maximal spring compression.
 
mfb's centre of mass approach is good. Alternatively, consider what the relationship is between the velocities when the spring is at maximum compression.
What conservation laws do you know that might be useful?
 
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