- #1
calvert11
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Homework Statement
Solve the IVP. Is your solution unique? Explain.
ty' + (t-2)y = (t^4)*(e^t)
y(0)=0
Homework Equations
Theorem:
If p(t) and g(t) are continuous functions on an open interval a< t < b and the interval contains t0, then there is a unique solution to the IVP on that interval.
The Attempt at a Solution
I'm rather sure I've solved the equation correctly, but I end up with something like this:
y = [tex]\frac{t^2}{e^t}[/tex] X [...etc.]
Now if I input the initial values, I get 0 = 0.
Furthermore, since p(t) = (t-2)/t where t cannot = 0, the Theorem would fail as no interval exists that satisfies it.
So, I'm a bit confused about how to answer this question. Assuming I solved the equation correctly, is 0 = 0 a solution? And since the equation fails the Theorem does that mean it is not unique? I do hope I'm making sense.