zak100 said:
Hi,
Okay, 0.6 is also logical, so for question in this thread I have for the combine 2 years books read by her are:
0.6 + 0.4 = 17 + 3x but now i am getting the answer in minus.
Whats getting wrong when i am considering the whole 100%. There are only two books, if composition of french is 60% then composition of English should be 40% but why its not working.
Some body please tell me my mistake.
Zulfi.
Your mistake is that 0.6 + 0.4 = 17 + 3x is not the correct equation to use here.
To recapitulate the problem statement:
zak100 said:
Homework Statement
In 1999, Diana read 10 English books and 7 French books. In 2000, she read twice as many French books as English books. If 60% of the books that she read during the two years were French, how many books did she read in 2000?
First of all, forget the 0.40. That doesn't come into consideration at all.
Figure out how many French books Diana read in 1999 and 2000, using what information is given in the statement above.
You are told she read 7 French books in 1999, and 10 English books. How many books did Diana read in 1999?
In 2000, Diana read twice as many French books as English books. Since the number of English books or French books read is unknown, you would pick one kind of book and say that Diana read x of them in 2000.
So, the next step here is to express the number of books which Diana read in 2000.
Write an expression for the total number of books Diana read in 1999 and 2000.
60% of this total number of books read is equal to the number of French books Diana read in 1999 and 2000. How would you express this?
Solve this last expression for x, and then calculate the number of books Diana read in 2000.