Linear Independence of vectors question

bossman007
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Homework Statement



Suppose that A, B and C are not linearly independent. Then show how the a_i can be computed, up to a common factor, from the scalar products of these vectors with each other

Homework Equations



a_1A + a_2B + a_3C = 0

a_1=a_2=a_3=0

Hint - Suppose that there are non-zero values of the a_i's that satisfy
a_1A + a_2B + a_3C = 0. Then, taking the dot product of both sides of this equation with A will yield a set of equations that can be solved for the a_i's

The Attempt at a Solution



a_1AA + a_2BA + a_3CA=0

no idea where to go from here, I took the dot product of both sides but confused from the wording of the question what my next step should be, or If I did my dot product right
 
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Do the same with B and C. The scalar product are numbers, so you have a system of equations for the three unknown parameters. As the vectors are not independent, one of the parameter can be chosen arbitrary. Solve the system of equations for the other two coefficients.

ehild
 
Thank you for your reply. you're saying arbitrarily choose a value? If so, I chose a_1=1

from that, my set of equations looks like, after moving the AA , AB and AC to the other side of the equation i get this:

a_2AB + a_3AC = -AA
a_2BB + a_3BC = -AB
a_2BC + a_3CC = -AC

**any vector combination above is a dot product, I just didnt know how to latex code it***

I went on to try substitution to solve for a_2, but the result was messy and didnt seem like I was on the right track. Am I on the right track?
 
It will not be that messy. Multiply the first equation with BC, the second equation with AC. Subtract them. a3 cancels and you can isolate a2.

ehild
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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