Linear Momentum Algebraic interpretation

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SUMMARY

The discussion centers on the algebraic interpretation of linear momentum in relation to kinetic energy for two objects of differing masses. It establishes that when two objects have the same kinetic energy, the object with greater mass will possess more momentum. The key equations utilized include the kinetic energy formula, KE = 1/2 mv², and the relationship between momentum (p = mv) and kinetic energy. A suggested approach involves expressing velocity in terms of momentum to derive the relationship between kinetic energies and momenta.

PREREQUISITES
  • Understanding of kinetic energy equations (KE = 1/2 mv²)
  • Familiarity with momentum concepts (p = mv)
  • Basic algebraic manipulation skills
  • Knowledge of mass and its impact on momentum
NEXT STEPS
  • Explore the derivation of momentum from kinetic energy equations
  • Study the implications of mass on momentum in different physical scenarios
  • Investigate the relationship between kinetic energy and momentum quantitatively
  • Learn about conservation laws in physics, particularly momentum conservation
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in understanding the relationship between kinetic energy and momentum in physical systems.

brycenrg
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Homework Statement


A light object and a heavy object have the same kinetic energy. Which has more momentum?

Homework Equations


I am trying to prove this through algebra.
I don't understand how to show this any help?

The Attempt at a Solution


1/2m1v1^2 = 1/2m2v2^2 when m1 > m2

v1 = v2 squareroot(m2/m1)

m1v2 squareroot(m2/m1) = m2v1 squareroot(m1/m2)
 
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brycenrg said:

Homework Statement


A light object and a heavy object have the same kinetic energy. Which has more momentum?

Homework Equations


I am trying to prove this through algebra.
I don't understand how to show this any help?

The Attempt at a Solution


1/2m1v1^2 = 1/2m2v2^2 when m1 > m2

v1 = v2 squareroot(m2/m1)

m1v2 squareroot(m2/m1) = m2v1 squareroot(m1/m2)

I do not see what is the sense of your last line. What are the momenta?
 
I suggest you work in the other direction and do not use v as a variable. Instead, solve for v from p = mv and insert this into the expression for kinetic energy.
 
Here's a hint. You do have to use algebra here, but this is only a qualitative question where you have to find the relationship

## \frac{KE_1}{KE_2} = constant = \alpha(m_1, m_2) \frac{p_1^2}{p_2^2} ##

where ## \alpha ## is a function of the two masses. Once you find this relationship, you can answer the question easily.

Goodluck! ;)
 

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