Linear Transformations using polynomials

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SUMMARY

The discussion focuses on the linear transformation D defined on the space of polynomials P3, where D takes the derivative of a polynomial. The matrix representation MD of D with respect to the standard basis {1, x, x², x³} is derived by applying D to each basis element, resulting in MD = [0 1 2 3; 0 0 1 2; 0 0 0 1; 0 0 0 0]. The conclusion is that (MD)⁴ = 0 because repeated differentiation reduces the degree of any polynomial until it reaches zero, leading to the zero polynomial.

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  • Understanding of polynomial functions and their degrees
  • Knowledge of linear transformations and their matrix representations
  • Familiarity with differentiation and its effects on polynomial degree
  • Basic concepts of vector spaces and basis elements
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mbud
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Homework Statement



Let P3 be the space of all polynomials (with real coefficients) of degree at most 3. Let
D : P3 -> P3 be the linear transformation given by taking the derivative of a polynomial.
That is
D(a + bx + cx2 + dx3) = b + 2cx + 3dx2:
Let B be the standard basis {1; x; x2; x3} of P3.
(a) Find the matrix MD of D with respect to the standard basis.
(b) Explain, without doing any matrix calculations, why (MD)4 = 0.

Homework Equations





The Attempt at a Solution


i know it may be a simple question but i don't even know where to begin
but in a attempt is
MD = [1 1 1 1;
0 2 3 0]
 
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Welcome to PF!

Hi mbud! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)
mbud said:
Let P3 be the space of all polynomials (with real coefficients) of degree at most 3. Let
D : P3 -> P3 be the linear transformation given by taking the derivative of a polynomial.
That is
D(a + bx + cx2 + dx3) = b + 2cx + 3dx2:
Let B be the standard basis {1; x; x2; x3} of P3.
(a) Find the matrix MD of D with respect to the standard basis.
(b) Explain, without doing any matrix calculations, why (MD)4 = 0.

To find M, you only need the effect of M on the four basis elements. Sooo …

Hint: what is x2 as a vector? what is Dx2 as a vector? :wink:
 
More specifically, since the standard basis is 1, x, x2, and x3, take the derivative of each and write it in terms of those. The coefficients give each column of the matrix.
 
Thanks, for the help, but i still don't know how to explain (MD)^4 = 0
I can show it using matrices, but when it comes to words, I am flabbergasted.
 
mbud said:
Thanks, for the help, but i still don't know how to explain (MD)^4 = 0
I can show it using matrices, but when it comes to words, I am flabbergasted.

Hint: if V is the vector form of a polynomial ax3 + bx2 + cx + d, what is (MD)4V the vector of? :wink:
 
Differentiation does what to the degree of a polynomial? This is nothing to do with vectors, or vector spaces, or matrices - sometimes you just have to look at things and think for a little bit.
 

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