A Is 'Local Flatness' the Right Term for Describing Spacetime?

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I see many posts by several different people referring to spacetime being "locally flat" with the intended meaning of being locally indistinguishable from Minkowski space, i.e., being able to rewrite the metric on orthonormal form and not being able to measure curvature on some local scale. I do not think this is an appropriate nomenclature and the more appropriate nomenclature would be to refer to a local inertial frame. I am aware that some textbook authors, such as Schutz, use the term in this way as well. These are (some of) my issues with the terminology:
  • "Local flatness" is typically defined in a different manner in topology, where it is a property of a submanifold. The entire point of using differential geometry is that spacetime can be described without reference to it being a submanifold of some higher-dimensional space.
  • Not withstanding the previous point, we otherwise use "local" to describe a property that is only true in a point or in a neighbourhood of that point. "Flat" refers to the curvature being zero. Putting those two together as "locally flat" would therefore typically mean that the curvature at the given event (or neighbourhood) would be zero. This is not generally true as curvature invariants can be computed to be non-zero even though there are local inertial frames at all events.
  • There exists other alternative terminology to describe precisely the ideas that "locally flat" intends to convey. The existence of a "local inertial frame" or similar comes to mind.
Any thoughts? Am I just being picky?
 
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Orodruin said:
Any thoughts? Am I just being picky?
I think you have a perfectly valid point. It can be misleading and confusing, it is sloppy, and it is incorrect. So, it should be avoided. And it isn't that much trouble to use the right terminology. I am perfectly fine with abuse of terminology and notations, but this goes too far, and dosen't save anything.
 
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I think you are being picky, but of course it is consistent with a distinguished tradition of complaining with proponents like Synge and Ohanian.

I have never been able to understand this Principle… Does it mean that the effects of a gravitational field are indistinguishable from the effects of an observer’s acceleration? If so, it is false. In Einstein’s theory, either there is a gravitational field or there is none, according as the Riemann tensor does not or does vanish. This is an absolute property; it has nothing to do with any observer’s world-line. Spacetime is either flat or curved… The Principle of Equivalence performed the essential office of midwife at the birth of general relativity, but… I suggest that the midwife be now buried with appropriate honors and the facts of absolute space-time faced.
https://www.mathpages.com/home/kmath622/kmath622.htm
 
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As far as I understand curvature is an observable in GR and has a coordinate independent meaning. Minkowski space has identically 0 curvature and doesn't exist in the wild. What is unclear to me is the assertion that all observable effects of curvature vanish in the small. I don't think you are being picky.
 
A quick look for "locally flat" at the indices of some textbooks:
Wald: Not in index.
Carroll: Not in index. Refers to this as "local inertial frame/coordinates" or "local Lorentz frame" for the corresponding basis vectors.
Guidry: Not in index.
Schutz: Introduces the term as equivalent to "local inertial coordinates", then uses "locally flat".
MTW: Not in index. Uses "local inertial frame/coordinates".
 
Orodruin said:
Any thoughts?

I used "locally flat" in a B-level thread recently. It seemed like the simplest way to get across the point I was trying to make to that particular poster.

In a more advanced thread I would favor "local inertial frame" or something like it instead.
 
Isn't any differentiable manifold in some of the vague senses given above "locally flat"? In a physicist's sloppy language one could simply define a differential manifold as a manifold which locally looks like an affine space, and an affine space is flat by definition.
 
  • #10
PeterDonis said:
I used "locally flat" in a B-level thread recently. It seemed like the simplest way to get across the point I was trying to make to that particular poster.

In a more advanced thread I would favor "local inertial frame" or something like it instead.

The risk we run by using "locally flat" when we mean "local inertial frame" is two-fold in my view. The first risk is that it teaches someone the wrong nomenclature, even if it conveys the concept. This is something that then spreads and has to be corrected at a later stage. The second is that people that see it and know better either dismiss the post or (worse) start arguing in-thread about the correct nomenclature - quickly escalating a B-level thread to A-level.

I do not think much is lost on B-level by instead saying that spacetime is indistinguishable from Minkowski space if you just look at a small enough region of it.
 
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  • #11
vanhees71 said:
In a physicist's sloppy language one could simply define a differential manifold as a manifold which locally looks like an affine space, and an affine space is flat by definition.
The point is that it looks flat only from the view of having a local diffeomorphism. The connection on the manifold is not considered here (which is what is really being referenced when you say "flat" versus "curved" - zero vs non-zero curvature).
 
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  • #12
Orodruin said:
"Local flatness" is typically defined in a different manner in topology, where it is a property of a submanifold. The entire point of using differential geometry is that spacetime can be described without reference to it being a submanifold of some higher-dimensional space.
I don't think that this is an issue. Terminology gets reused between different fields of study all the time.

Orodruin said:
Not withstanding the previous point, we otherwise use "local" to describe a property that is only true in a point or in a neighbourhood of that point. "Flat" refers to the curvature being zero. Putting those two together as "locally flat" would therefore typically mean that the curvature at the given event (or neighbourhood) would be zero. This is not generally true as curvature invariants can be computed to be non-zero even though there are local inertial frames at all events.
I agree here. "Flat" is not what is actually meant.

Orodruin said:
There exists other alternative terminology to describe precisely the ideas that "locally flat" intends to convey. The existence of a "local inertial frame" or similar comes to mind.
The phrase "local inertial frame" doesn't mean the same as "locally flat", since you can use non-inertial coordinates on a small region of curved spacetime and get a metric matching the non-inertial flat spacetime metric to first order.

I am not sure that any reference to local inertial frames correctly conveys that idea. Maybe "locally flat to first order"? But that seems weird too since curvature is a 2nd order phenomenon anyway (maybe that is the point).
 
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  • #13
Orodruin said:
MTW: Not in index. Uses "local inertial frame/coordinates".

MTW uses the term "local flatness" in 7.5, and "locally flat" in Box 6.1 and Section 20.4.
 
  • #14
Dale said:
The phrase "local inertial frame" doesn't mean the same as "locally flat", since you can use non-inertial coordinates on a small region of curved spacetime and get a metric matching the non-inertial flat spacetime metric to first order.
To zeroth order. If you have non-inertial coordinates then the Christoffel symbols are non-zero and they depend on the first derivatives of the metric components.

Either way, I was referring to stating the existence of a local inertial frame, not necessarily using it. This is the only meaning of ”locally flat” I have found in a GR textbook (Schutz, see anove).

atyy said:
MTW uses the term "local flatness" in 7.5, and "locally flat" in Box 6.1 and Section 20.4.
Thanks for the sections, I will check it out when I am back in office tomorrow. I do not keep it with me at all times since my squat PB all time is just 160 kg ... :rolleyes:
 
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  • #15
Dale said:
maybe that is the point
I guess my main issue is that ”flat” really has a different meaning in terms of the curvature tensor being zero and ”local” tends to refer to a point or neighbourhood. Putting those two together would seem to imply curvature being zero at a point or neighbourhood, which certainly is not the way it is being used. The fact that locally flat actually means something else in topology is secondary.
 
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  • #16
Orodruin said:
To zeroth order. If you have non-inertial coordinates then the Christoffel symbols are non-zero and they depend on the first derivatives of the metric components.
Yes, but I think that the first derivatives are the same as the equivalent non-inertial coordinate chart on Minkowski space. As far as I know they only differ from the flat spacetime version to second order. Is that incorrect?
Orodruin said:
Either way, I was referring to stating the existence of a local inertial frame, not necessarily using it. This is the only meaning of ”locally flat” I have found in a GR textbook (Schutz, see anove).
Ah, yes I missed that above.
 
  • #17
Doesn't the term locally flat mean that at point p with coordinates t,x,y,z in a curved space-time you can transform into a minkowski metric? Which is flat, and since that is only true at point p and nothing but p, it is local to p?
 
  • #18
I've always used locally flat for a Riemannian/pseudoriemannian manifold to mean that in a small enough region the geometry is "essentially" indistinguishable from Euclidean/Minkowski space. To formalize "essentially", you do get to coordinates that make the metric Euclidean or Minkowski at a point, with connection coefficients and metric first derivatives vanishing at this point. Thus, only second derivatives of the metric are nonvanishing if there is curvature. As a result, almost any geometric or physical measurement in a small region has only second order differences from flat space/spacetime.
 
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  • #19
atyy said:

One claim in this article seems questionable to me: that you can have, in the interior of some spacetime and bounded by curved regions separating it from a standard flat Minkowski spacetime region, a spacetime region which is flat but has "homogeneous acceleration" relative to the exterior flat region. I have never seen such a solution in the GR literature. Does anyone know what this refers to?
 
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  • #20
PAllen said:
I've always used locally flat for a Riemannian/pseudoriemannian manifold to mean that in a small enough region the geometry is "essentially" indistinguishable from Euclidean/Minkowski space. To formalize "essentially", you do get to coordinates that make the metric Euclidean or Minkowski at a point, with connection coefficients and metric first derivatives vanishing at this point. Thus, only second derivatives of the metric are nonvanishing if there is curvature. As a result, almost any geometric or physical measurement in a small region has only second order differences from flat space/spacetime.
Yes, I understand that this is the intended meaning in many cases. However, my issue is that it is a somewhat deceptive use of the words "local" and "flat". For example, Schwarzschild spacetime is locally flat everywhere with that meaning, however, nowhere is the curvature tensor of Schwarzschild spacetime zero, particularly not as you approach the singularity where curvature invariants blow up.

atyy said:
MTW uses the term "local flatness" in 7.5, and "locally flat" in Box 6.1 and Section 20.4.
I am more or less fine with the usage in Box 6.1 and section 7.5 as it can be interpreted to be talking about the tangent spaces and how to patch them together. I think the formulation in 20.4 is unfortunate.
 
  • #21
Orodruin said:
I am more or less fine with the usage in Box 6.1 and section 7.5 as it can be interpreted to be talking about the tangent spaces and how to patch them together. I think the formulation in 20.4 is unfortunate.

Hmm, but then how can a tangent space be flat? Usually I don't ascribe either flatness or non-flatness to the tangent space.
 
  • #22
atyy said:
Hmm, but then how can a tangent space be flat? Usually I don't ascribe either flatness or non-flatness to the tangent space.
The tangent space is naturally Minkowski space, so it is flat in that sense.
 
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  • #23
martinbn said:
The tangent space is naturally Minkowski space, so it is flat in that sense.

Minkowski space is an affine space. The tangent space a vector space, not an affine space.
 
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  • #24
atyy said:
Minkowski space is an affine space. The tangent space a vector space, not an affine space.
Any vector space V may be considered as an affine space over itself by considering (V,V) and there is always an isomorphism between an affine space and its tangent space defined by picking an origin. This is precisely the approximation we do when we locally ignore curvature.

Put slightly differently, the idea being conveyed is that a neighbourhood of an event is well described by using an orthonormal basis on the tangent space and the exponential map to define coordinates that will be a local inertial frame. The effects of ignoring curvature (if the spacetime is not flat) then appear only at second order in the metric components.
 
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  • #25
Orodruin said:
Any vector space V may be considered as an affine space over itself by considering (V,V) and there is always an isomorphism between an affine space and its tangent space defined by picking an origin. This is precisely the approximation we do when we locally ignore curvature.

Put slightly differently, the idea being conveyed is that a neighbourhood of an event is well described by using an orthonormal basis on the tangent space and the exponential map to define coordinates that will be a local inertial frame. The effects of ignoring curvature (if the spacetime is not flat) then appear only at second order in the metric components.

Ok, but then the Riemann normal coordinates are an expression of the fact that there is a flat tangent space at each point. So local inertial frame is local flatness.
 
  • #26
atyy said:
Ok, but then the Riemann normal coordinates are an expression of the fact that there is a flat tangent space at each point. So local inertial frame is local flatness.
This is where we diverge on what reasonable nomenclature is. I would use local inertial coordinates, not local flatness.
 
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  • #27
Orodruin said:
This is where we diverge on what reasonable nomenclature is. I would use local inertial coordinates, not local flatness.

I guess it is hard for me to understand what exactly is the difference between the idea in MTW Box 6.1 and section 7.5, which apparently is ok with you, but not section 20.4. They seem really closely related to me - instinctively, I'd say its usage in section 20.4 is the mathematical expression of the more qualitative language of Box 6.1 and section 7.5.
 
  • #28
atyy said:
I guess it is hard for me to understand what exactly is the difference between the idea in MTW Box 6.1 and section 7.5, which apparently is ok with you, but not section 20.4. They seem really closely related to me - instinctively, I'd say its usage in section 20.4 is the mathematical expression of the more qualitative language of Box 6.1 and section 7.5.
I think it boils down to differentiating between saying that the tangent space or something we approximate the manifold with is flat versus saying that the manifold itself is flat at a point or in a neighbourhood.
 
  • #29
atyy said:
I guess it is hard for me to understand what exactly is the difference between the idea in MTW Box 6.1 and section 7.5, which apparently is ok with you, but not section 20.4. They seem really closely related to me - instinctively, I'd say its usage in section 20.4 is the mathematical expression of the more qualitative language of Box 6.1 and section 7.5.
I, personally, would count any of these. These are general coments to give motivation based on something that is reasonbable and intiutive. But they do not give definitions, nor do they establish terminology that the follow in the book.
 
  • #30
Reading through all the answers, I indeed think that to call the equivalence principle (i.e., the existence of a local inertial reference frame at any point of the spacetime manifold) "local flatness" is highly misleading since the notion of flatness or non-flatness is a local concept itself, i.e., it's described by the vanishing or nonvanishing of the curvature tensor and as such is of course independent of the choice of the frame since it's a tensor property of the spacetime manifold.
 
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  • #31
OK, but hopefully everyone who objects to "local flatness" also objects to one of the traditional statements of the equivalence principle: gravity is locally equivalent to acceleration.
 
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  • #32
atyy said:
OK, but hopefully everyone who objects to "local flatness" also objects to one of the traditional statement of the equivalence principle: gravity is locally equivalent to acceleration.

There are clearly tensor properties of curved spacetime that are not equivalent to just having acceleration in Minkowski space (the tensor properties do not care about whether or not you use an inertial frame).

I think a better formulation would be "locally indistinguishable from" as measuring curvature requires parallel transport around small loops returning small^2 changes in the transported vectors. This makes reference to the measuring procedure rather than the mathematical formulation.

Of course, in the end this just underlines the difficulty in inventing a precise enough popular language to use when we engage in B- and I-level threads on GR. I mean, I am sure (or assume) that we all agree on the actual maths involved in GR, the issue is one of nomenclature alone.
 
  • #33
Orodruin said:
Of course, in the end this just underlines the difficulty in inventing a precise enough popular language to use when we engage in B- and I-level threads on GR. I mean, I am sure (or assume) that we all agree on the actual maths involved in GR, the issue is one of nomenclature alone.

But if it weren't for all this terrible language, we wouldn't have the pleasure (?) of radiating charge and the equivalence principle threads from time to time :P

Orodruin said:
I think a better formulation would be "locally indistinguishable from" as measuring curvature requires parallel transport around small loops returning small^2 changes in the transported vectors. This makes reference to the measuring procedure rather than the mathematical formulation.

BTW, Ohanian even objected to this in this old paper of his: https://doi.org/10.1119/1.10744
"The strong principle of equivalence is usually formulated as an assertion that in a sufficiently small, freely falling laboratory the gravitational fields surrounding the laboratory cannot be detected. We show that this is false by presenting several simple examples of phenomena which may be used to detect the gravitational field through its tidal effects; we show that these effects are, in fact, local (observable in an arbitrarily small region)."

It's pretty much like the famous objection by Synge I mentioned earlier.
 
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  • #34
atyy said:
But if it weren't for all this terrible language, we wouldn't have the pleasure (?) of radiating charge and the equivalence principle threads from time to time :P
BTW, Ohanian even objected to this in this old paper of his: https://doi.org/10.1119/1.10744
"The strong principle of equivalence is usually formulated as an assertion that in a sufficiently small, freely falling laboratory the gravitational fields surrounding the laboratory cannot be detected. We show that this is false by presenting several simple examples of phenomena which may be used to detect the gravitational field through its tidal effects; we show that these effects are, in fact, local (observable in an arbitrarily small region)."

It's pretty much like the famous objection by Synge I mentioned earlier.
The mathpages article you linked previously has a pretty effective refutation of Ohanian's examples, to whit, they all ignore (sometime subtly) the time aspect of local spacetime region.

Synge's objection is purely mathematical, and amounts to the same as Orodruin's - that curvature is defined at each point of the manifold.

The charged particle debates (classically) all boil down to the fact that radiation is not a strictly local phenomenon, and can be shown to follow from inability to construct a global inertial frame.

However, I do share the same question Peter raised about one part of this article, and I also choose not to accept Einstein's definition of gravity, as described therein (this being purely a choice of terminology).
 
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  • #35
For Riemannian manifolds, I have seen the term “locally Euclidean” used. This avoids the flat vs curved conundrum, while also not having to discuss coordinates. Would the “locally Minkowski” make you @Orodruin happy?
 
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  • #36
Is there a microscopic description of these "tidal forces" - that (if I understand correctly) betray non-zero curvature even in an infinitesimal inertial frame?

https://en.wikipedia.org/wiki/Tidal_tensor

My cartoon is that they represent (result from) geometric phase or "Pancharatnam-Berry Phase" (non-zero holonomy)?

I get that there is a frequency shift (in light for example) as a function of a gravitational field (gravitational lensing). But my understanding of that is that it would not be detectable from within the inertial frame?

Are there any experiments that would detect a changing value of the field (curvature) from inside an inertial frame? Is there just some simple electrostatic gradient effect that can be measured? I was assuming the answer is no?

Would the Aharonov-Bohm effect reflect such change? Not sure how that effect is measured but I gather it's not just a simple magnetometer.

Would the spontaneous collapse of entanglement (somehow absent other causes) be indicative, or some change in the stability of entanglement as a function of alignment with the change (gradient) in the field?
 
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  • #37
PAllen said:
The mathpages article you linked previously has a pretty effective refutation of Ohanian's examples, to whit, they all ignore (sometime subtly) the time aspect of local spacetime region.

Interesting! I only linked the mathpages article for Synge's remark and had not read the rest of it. I wonder whether Ohanian includes these in the latest edition of his textbook with Ruffini.
 
  • #38
Jimster41 said:
Is there a microscopic description of these "tidal forces" - that (if I understand correctly) betray non-zero curvature even in an infinitesimal inertial frame?

https://en.wikipedia.org/wiki/Tidal_tensor

My cartoon is that they represent (result from) geometric phase or "Pancharatnam-Berry Phase" (non-zero holonomy)?

I get that there is a frequency shift (in light for example) as a function of a gravitational field (gravitational lensing). But my understanding of that is that it would not be detectable from within the inertial frame?

Are there any experiments that would detect a changing value of the field (curvature) from inside an inertial frame?

Would the spontaneous collapse of entanglement (somehow absent other causes) be indicative, or some change in the stability of entanglement as a function of alignment with the change in the field?

Would the Aharonov-Bohm effect reflect such change? Not sure how that effect is measured but I gather it's not just a simple magnetometer.
I would say that the SEP (strong equivalence principle) is a testable proposition, and that if any test could be devised that, when performed in an arbitrarily small spacetime region with any finite precision, could distinguished a local inertial frame in a region with curvature from one without, you would have a violation of SEP.

The SEP is making a claim that local physics is precisely as indistinguishable from SR as local geometry is from Euclidean for a Riemannian metric. If you look at the various equivalent definitions of geometric curvature, they all require infinite precision to execute:
- limit of change of vector transported around quadrilateral as its size goes to zero divided by the area. The actual change goes to zero, and still goes to zero if divided by e.g. a diagonal of the quadrilateral.
- limit of angular defect in a triangle as its size goes to zero, divided by the area of the triangle. Again, the angular defect itself goes to zero, and you need the division by area to measure the second order effect.
- limit of the difference between 1 and ratio of circumference or area to the euclidean formula, divided by area, as the size goes to zero. The ratios themselves go to 1, and the difference from 1 still goes to zero if divided by circle diameter.
 
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  • #39
@Orodruin
I agree that it is misleading. I'd like to make two points.

First, comparable uses of the word 'locally' in topology agree with your principle that the property must apply in some neighbourhood of each point - which flatness does not. The examples I think of are locally connected, locally path connected and locally compact. 'Locally flat' does not adhere to this principle. There is no neighbourhood of a point in which the curvature is constant at zero. So use of the term 'locally flat' does not follow standard practice for the term 'locally' in topology.

Second, is it not the case that, if we exclude singularities from a spacetime manifold (which IIRC we can do without inhibiting our ability to calculate) then any achievable spacetime manifold is everywhere 'locally flat'? I am not completely sure of that, or whether 'local flatness' may not apply at the event horizon of a black hole. But if I guessed correctly, then saying a spacetime is locally flat is saying nothing, and we lose nothing by discarding the phrase.

I would have thought that saying the spacetime is differentiable (or ##C^n## for some ##n##) tells us all that is needed. It would be better to simply say that we can approximate a spacetime to an arbitrarily high degree of accuracy near a point by taking a small enough neighbourhood of the point.
 
  • #40
andrewkirk said:
@OrodruinSecond, is it not the case that, if we exclude singularities from a spacetime manifold (which IIRC we can do without inhibiting our ability to calculate) then any achievable spacetime manifold is everywhere 'locally flat'? I am not completely sure of that, or whether 'local flatness' may not apply at the event horizon of a black hole. But if I guessed correctly, then saying a spacetime is locally flat is saying nothing, and we lose nothing by discarding the phrase.
I don’t know what you mean here. @orodruin’s complaint is that most useful GR manifold’s (Schwarzschild, Kerr, FLRW, etc.) are nowhere flat, though the first two are asymptotically flat at spatial infinity.

On the other hand, the definition of equipping a manifold with a metric requires that it be locally Euclidean or Minkowski to second order. This is all mathematical definition. The physical question is then whether such models with a mapping to measurements correspond to reality.

The singularity can’t be part of the manifold - it isn’t a choice. And no part of the manifold, horizon or arbitrarily close to a singularity can avoid being locally Minkowski or Euclidean, because the definition Riemannian or pseudoriemannian forces this by design.
 
  • #41
PAllen said:
@orodruin’s complaint is that most useful GR manifold’s (Schwarzschild, Kerr, FLRW, etc.) are nowhere flat, though the first two are asymptotically flat at spatial infinity.
Yes, I understand that that is part of Orodruin's point, and I agree with it. But I don't understand why you think what I wrote does not agree with that.
 
  • #42
PAllen said:
For Riemannian manifolds, I have seen the term “locally Euclidean” used. This avoids the flat vs curved conundrum, while also not having to discuss coordinates. Would the “locally Minkowski” make you @Orodruin happy?
It is better, although I am not completely sure how I feel about it yet. I have to sleep on it I think.
 
  • #43
andrewkirk said:
Yes, I understand that that is part of Orodruin's point, and I agree with it. But I don't understand why you think what I wrote does not agree with that.
Perhaps I misunderstood you. Your first paragraph seemed to reject local flatness, while your second embraced it. But I think I missed the significance of your scare quotes.

In that case, whatever the best term is, I think it is crucial to know that equipping a manifold with a metric intentionally gives it some universal local properties. And your comment about the horizon is exactly why it is crucial - a horizon is locally indistinguishable from my living room per GR. We need a name for this property that tells you it is impossible to say things like time stops at the horizon in GR.
 
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  • #44
My understanding of "local flatness" is the following. Around any spacetime point (with local flatness), there exists a region of spacetime (a neighborhood) within which the results of any experiment cannot be distinguished from the results of an experiment performed in completely flat spacetime. In other words, there is some region around the point such that, should you perform an experiment there, you would not be able to take the results and prove that special relativity is not the "true" theory (more simply, that special relativity is not valid) in that region of spacetime. If you do perform such an experiment and can show that SR is not valid, then you have chosen too large a neighborhood.

If I am misinterpreting this, I'd welcome feedback as this is something I am trying to learn in more detail.
 
  • #45
Orodruin said:
I see many posts by several different people referring to spacetime being "locally flat" with the intended meaning of being locally indistinguishable from Minkowski space, i.e., being able to rewrite the metric on orthonormal form and not being able to measure curvature on some local scale. I do not think this is an appropriate nomenclature and the more appropriate nomenclature would be to refer to a local inertial frame. I am aware that some textbook authors, such as Schutz, use the term in this way as well. These are (some of) my issues with the terminology:
  • "Local flatness" is typically defined in a different manner in topology, where it is a property of a submanifold. The entire point of using differential geometry is that spacetime can be described without reference to it being a submanifold of some higher-dimensional space.
  • Not withstanding the previous point, we otherwise use "local" to describe a property that is only true in a point or in a neighbourhood of that point. "Flat" refers to the curvature being zero. Putting those two together as "locally flat" would therefore typically mean that the curvature at the given event (or neighbourhood) would be zero. This is not generally true as curvature invariants can be computed to be non-zero even though there are local inertial frames at all events.
  • There exists other alternative terminology to describe precisely the ideas that "locally flat" intends to convey. The existence of a "local inertial frame" or similar comes to mind.
Any thoughts? Am I just being picky?

Yes, I am bothered by this also.
I am concerned that most of the mathematics that physics uses only applies to flat spacetime.
I call this "flat spacetime prejudice."
I offered to teach an undergraduate class in general relativity to try to get more physicists fluent with curved space. I wonder if the trouble finding a unified field theory is hindered by the lack of workers.
For many reasons, it didn't happen.

To your question:
I don't feel qualified to answer your question.
I would really like to hear from a mathematician about this.

Maybe there is an answer in the many replies here.
 
  • #46
JustTryingToLearn said:
My understanding of "local flatness" is the following. Around any spacetime point (with local flatness), there exists a region of spacetime (a neighborhood) within which the results of any experiment cannot be distinguished from the results of an experiment performed in completely flat spacetime. In other words, there is some region around the point such that, should you perform an experiment there, you would not be able to take the results and prove that special relativity is not the "true" theory (more simply, that special relativity is not valid) in that region of spacetime. If you do perform such an experiment and can show that SR is not valid, then you have chosen too large a neighborhood.

If I am misinterpreting this, I'd welcome feedback as this is something I am trying to learn in more detail.
That is a correct statement of the Einstein Equivalence Principle as defined by e.g. Clifford Will. Its ability to be true in GR is, indeed, closely related to “local behavior of a pseudoRiemannian manifold”. The gist of this thread is what is the best compact verbal description of this local behavior that we all agree on the mathematics of. The equivalence principle names the physics. What we seek consensus on is a name for corresponding math of the manifold.
 
  • #47
Orodruin said:
I think a better formulation would be "locally indistinguishable from" as measuring curvature requires parallel transport around small loops returning small^2 changes in the transported vectors. This makes reference to the measuring procedure rather than the mathematical formulation.
PAllen said:
The mathpages article you linked previously has a pretty effective refutation of Ohanian's examples, to whit, they all ignore (sometime subtly) the time aspect of local spacetime region.
PAllen said:
I would say that the SEP (strong equivalence principle) is a testable proposition, and that if any test could be devised that, when performed in an arbitrarily small spacetime region with any finite precision, could distinguished a local inertial frame in a region with curvature from one without, you would have a violation of SEP.

The SEP is making a claim that local physics is precisely as indistinguishable from SR as local geometry is from Euclidean for a Riemannian metric. If you look at the various equivalent definitions of geometric curvature, they all require infinite precision to execute:
- limit of change of vector transported around quadrilateral as its size goes to zero divided by the area. The actual change goes to zero, and still goes to zero if divided by e.g. a diagonal of the quadrilateral.
- limit of angular defect in a triangle as its size goes to zero, divided by the area of the triangle. Again, the angular defect itself goes to zero, and you need the division by area to measure the second order effect.
- limit of the difference between 1 and ratio of circumference or area to the euclidean formula, divided by area, as the size goes to zero. The ratios themselves go to 1, and the difference from 1 still goes to zero if divided by circle diameter.

So if we have infinite precision, are we able to detect deviations from flatness, even at a point? For example, could geodesic deviation be detected? In other words, is there a physical counterpart to the objection to the terminology of "local flatness"?
 
  • #48
atyy said:
So if we have infinite precision, are we able to detect deviations from flatness, even at a point?
Clearly not. If we have infinite precision we can detect deviations from flatness using measurements drawn from a neighborhood of arbitrarily small extent. But not from a neighborhood with no extent.
 
  • #49
jbriggs444 said:
Clearly not. If we have infinite precision we can detect deviations from flatness using measurements drawn from a neighborhood of arbitrarily small extent. But not from a neighborhood with no extent.

But the definition of curvature (ie to mathematically say that the curvature is non-zero at a point) also requires a neighbourhood?
 
  • #50
atyy said:
But the definition of curvature (ie to mathematically say that the curvature is non-zero at a point) also requires a neighbourhood?
Same as a derivative, f'(x). It is defined for a point but the definition depends on behavior near the point.

Or, consider the definition of a limit of a function at a point. The definition is for a point but is independent of the function value at that point.
 
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