(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The full problem is y=e^(x/2) and y=e^(-x) revolved around the x-axis, from [ln6,ln12].

The part I'm struggling with is evaluating 2e^(ln12/2) and 2e^(ln6/2).

I am just reviewing for my Calculus 1 final.

2. Relevant equations

3. The attempt at a solution

[tex]2e^{(ln12/2)}[/tex]

[tex]2 e^{(1/2)(ln12)}[/tex]

[tex]2 (e^{1/2}), e^{ln12}=12, and 2(12)e^{1/2}???[/tex]

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# Homework Help: Log function e^(ln12/2)?

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