MHB Logarithm + Nepper's number Exercise

AI Thread Summary
To solve the equation 2e^(-x) = 3e^(0.1x), the first step is to manipulate the equation to isolate the exponential term. By multiplying through by e^x, the equation simplifies to 2 = 3e^(1.1x). Dividing both sides by 3 leads to (2/3) = e^(1.1x), which can be converted to logarithmic form as 1.1x = ln(2/3). Finally, solving for x gives x = ln(2/3) / 1.1. The discussion also touches on using LaTeX for formatting mathematical expressions.
Velo
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" Solve the equation:

2e^(-x) = 3e^(0.1x) "

I've been fiddling around with this and I have no idea what I'm supposed to do. I know the final answer should be something like:
x = [(2/3)log e] / 1,1

The only step I've managed to do was:
(2/3) x e^(-x) = e^(0.1x)

But after that, I don't know how to get the x out of the exponential.. Help would be appreciated :')
 
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We are given to solve:

$$2e^{-x}=3e^{0.1x}$$

My first step would be to multiply though by $e^x\ne0$ to get:

$$2=3e^{1.1x}$$

Now divide though by 3:

$$\frac{2}{3}=e^{1.1x}$$

Next, what do you get when converting from exponential to logarithmic form?
 
Hm...

1.1x = log e ^ (2/3) <=>
x = [log e ^ (2/3)]/1.1 <=>
x = [(2/3) log e]/1.1

Which was the solution :o Is that right? Also, sorry, I'm having trouble using the latex thingy ><
 
Velo said:
Hm...

1.1x = log e ^ (2/3) <=>
x = [log e ^ (2/3)]/1.1 <=>
x = [(2/3) log e]/1.1

Which was the solution :o Is that right? Also, sorry, I'm having trouble using the latex thingy ><

Let's go back to:

$$\frac{2}{3}=e^{1.1x}$$

Now recall that:

$$a=b^c\implies c=\log_b(a)$$

And so we may write:

$$1.1x=\ln\left(\frac{2}{3}\right)$$

And then on dividing though by 1.1, we get:

$$x=\frac{\ln\left(\dfrac{2}{3}\right)}{1.1}$$

To use $\LaTeX$, you need to enclose your code with tags. The simplest way is to click the $\Sigma$ button on our toolbar, and then the cursor will be located in between the resulting $$$$ tags, and you can add your code there. You will find most symbols/commands you need to the right of the editor, in the "Quick $\LaTeX$" tool, and you can get quick previews of your code in our "$\LaTeX$ Live Preview" tool.
 
Ohhh, I get it now.. I read the book wrong too :') The solution had $$ \log_e(\frac{2}{3}) $$ and not $$\log(\frac{2}{3})$$.. I spent so much time wondering where that log had come from :') I tried redoing that exercise and the next in my notebook and I'm doing alright now x3 Thank you very much! :D
 
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