Lone pair angles in H2O

  • Thread starter alingy1
  • Start date
  • #1
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Homework Statement



What are the angles between lone pairs in H2O? I know that the bonds are separated by 109.5°. What about the lone pair angles? I googled everything. I found nothing. I cannot directly assume it is 109.5°... I have a basic knowledge of VSEPR.
 

Answers and Replies

  • #2
DrDu
Science Advisor
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I know that the bonds are separated by 109.5°.
Really? I thought it was 104.45 degrees.
In VSEPR, both bonding and lone pairs should be distributed approximately along the corners of a tetrahedron. Lone pairs are a bit more space filling than bonding pairs, so that the angle between the lone pairs is somewhat larger.
 
  • #3
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I will double check my answers before posting.
 
Last edited:
  • #4
Borek
Mentor
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H2O is bent. 109.5

H2O is bent, but 109.5 is incorrect. Water molecule is not tetrahedral. DrDu already posted a correct value.
 

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