1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Lone pair angles in H2O

  1. Nov 5, 2013 #1
    1. The problem statement, all variables and given/known data

    What are the angles between lone pairs in H2O? I know that the bonds are separated by 109.5°. What about the lone pair angles? I googled everything. I found nothing. I cannot directly assume it is 109.5°... I have a basic knowledge of VSEPR.
     
  2. jcsd
  3. Nov 6, 2013 #2

    DrDu

    User Avatar
    Science Advisor

    Really? I thought it was 104.45 degrees.
    In VSEPR, both bonding and lone pairs should be distributed approximately along the corners of a tetrahedron. Lone pairs are a bit more space filling than bonding pairs, so that the angle between the lone pairs is somewhat larger.
     
  4. Nov 14, 2013 #3
    I will double check my answers before posting.
     
    Last edited: Nov 15, 2013
  5. Nov 15, 2013 #4

    Borek

    User Avatar

    Staff: Mentor

    H2O is bent, but 109.5 is incorrect. Water molecule is not tetrahedral. DrDu already posted a correct value.
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted