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Lone pair angles in H2O

  1. Nov 5, 2013 #1
    1. The problem statement, all variables and given/known data

    What are the angles between lone pairs in H2O? I know that the bonds are separated by 109.5°. What about the lone pair angles? I googled everything. I found nothing. I cannot directly assume it is 109.5°... I have a basic knowledge of VSEPR.
     
  2. jcsd
  3. Nov 6, 2013 #2

    DrDu

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    Science Advisor

    Really? I thought it was 104.45 degrees.
    In VSEPR, both bonding and lone pairs should be distributed approximately along the corners of a tetrahedron. Lone pairs are a bit more space filling than bonding pairs, so that the angle between the lone pairs is somewhat larger.
     
  4. Nov 14, 2013 #3
    I will double check my answers before posting.
     
    Last edited: Nov 15, 2013
  5. Nov 15, 2013 #4

    Borek

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    Staff: Mentor

    H2O is bent, but 109.5 is incorrect. Water molecule is not tetrahedral. DrDu already posted a correct value.
     
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