Lorentz contraction and simultaneous detection of the ends of the moving rod?

In summary, the two equations that describe the behavior of a moving object in different reference frames are: Eq. (1) is the equation that describes the behavior of a moving object in an inertial reference frame and Eq. (2) is the equation that describes the behavior of a moving object in a non-inertial reference frame.
  • #1
bernhard.rothenstein
991
1
It is known that with the formula that accounts for the time dilation effect in hand we can derive directly the formula that accounts for the length contraction effect:
L0/Dt=L/(Dt)0 (1)
where L0 and (Dt)0 are proper length and proper time intervals, L and Dt representing measured length and coodinate time interval. From (1)
L=L0(1-V2/c2)1/2 (2)
Is there a special reason (Ockham's razor) for deriving (2) involving the Lorentz transformations and to perform a simultaneous detection of the space coordinates of the moving rod?
I find in the literature of the subject derivations of (2) considering that the two ends are detected at different times. Does the simple derivation (2) involve simultaneous detection of the ends of the rod?
Thanks for your answer.
 
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  • #2
Your Eq. (2) requires simultaneous detection of the ends of the rod.
The probable motivation for this is that simultaneous detection works in non-relativistic physics. Why should it be expected to work in SR?
 
  • #3
clem said:
Your Eq. (2) requires simultaneous detection of the ends of the rod.
The probable motivation for this is that simultaneous detection works in non-relativistic physics. Why should it be expected to work in SR?

Thanks for your answer. Let K0 be standard synchronized clocks located along the x-axis of the I inertial reference frame. Let K'0 a clock of the I' inertial reference frame located at its origin O' moving with velocity V relative to I. Observers from I measure the velocity of the moving clock using a rod of proper length L and the clocks K0 and K located at the two ends of the rod respectively reading t=0 and t respectively when the moving clock passes in front of them. By definition the speed of the moving clock is
V=L0/(t-0) (1)
measured as a quotient between a proper length and a coordinate time interval.
In a second experiment an observer R' located at the origin O' of I' uses clock K' as a wrist watch and measures the velocity of the moving rod used in the previous experiment. He detects the presence of the moving rod in front of him during a proper time interval (t'-0) measured as a difference between the readings of his wrist watch when the two ends of the rod cross his location respectively and measures a length L of the rod different from L0. By definition
V=L/(t'-0) (2)
the detection of the two ends being not simultaneous!
From (1) and (2) and taking into account the formula that accounts for the time dilation effect we receover the formula that accounts for the length contraction effect
L=L0(1-V2/c2)1/2.
 
  • #4
Sorry, I am better at algebra than lengthy discussion. I can't follow your discussion and don't have time to try. I hope someone else can help you.
 

Related to Lorentz contraction and simultaneous detection of the ends of the moving rod?

1. What is Lorentz contraction?

Lorentz contraction is a phenomenon described by the theory of special relativity, where objects appear to be shorter in the direction of their motion when observed from a stationary frame of reference.

2. How does Lorentz contraction affect the length of a moving rod?

According to the theory of special relativity, the length of a moving rod will appear shorter to an observer in a stationary frame of reference due to Lorentz contraction. This contraction is only noticeable at speeds close to the speed of light.

3. What is simultaneous detection of the ends of a moving rod?

Simultaneous detection of the ends of a moving rod refers to the ability to determine the position of both ends of a rod at the same time from a stationary frame of reference. This can be challenging due to the effects of time dilation and length contraction at high speeds.

4. Can the ends of a moving rod be detected simultaneously in all frames of reference?

No, simultaneous detection of the ends of a moving rod is only possible in frames of reference that are not moving relative to the rod. In other frames of reference, the positions of the ends may be perceived as different due to the effects of time dilation and length contraction.

5. How does the speed of the rod affect the ability to detect its ends simultaneously?

The faster the rod is moving, the more difficult it becomes to detect the position of its ends simultaneously. This is because the effects of time dilation and length contraction become more pronounced at higher speeds, making it more challenging to accurately determine the position of the ends of the rod in different frames of reference.

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