% lost to liquid crystal filters

AI Thread Summary
Liquid crystal filters polarize incoming light by bending it towards a specific angle, which results in some percentage of light loss. The exact percentage loss can vary based on the design and application of the filter. The functionality of liquid crystal displays (LCDs) relies on the ability of the liquid crystal layer to rotate the plane of light polarization when a voltage is applied. A front polarizer is essential in LCDs to ensure that only appropriately polarized light reaches the liquid crystal layer. For detailed explanations and diagrams, resources like Wikipedia and HowStuffWorks are recommended.
tmh556
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Hi,
I've got a random question. To my knowledge a liquid crystal filter bends incoming light coming in from various angles towards one particular angle as light leaves the filter. Does anybody know the % loss of light caused by this action?
 
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Liquid crystal filters are to polarize light.
Try looking with that keyword.
 
As NoTime says, LCDs work because of the ability of the liquid crystal layer to either rotate the plane of the incoming light polarization, or not (depending on whether there is a voltage applied across the LC layer). So to turn LC pixels on and off, a voltage is applied across the pixel. Different LCD designs either turn on the pixel or turn it off when the voltage is applied, but that's irrelvant to your question.

But for the LC layer to cause the pixel to be on or off based on whether the polarization is rotated or not, the incoming light going through the LC layer of the pixel must be polarized first. That is the job of the front polarizer in the LCD -- to present only appropiriately-polarized light to the LC layer of the cell. If you search on wikipedia.org or howstuffworks.com about liquid crystal displays, they should have some good diagrams and explanations.
 
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