Lottery Combinations Homework: Solving for Guaranteed Matches

AI Thread Summary
To guarantee at least one matching number in a lottery game where three numbers are drawn from a set of six, a student needs to buy two tickets, such as 1,2,3 and 4,5,6. For at least two matches, the student would need to calculate combinations using the formula for choosing two numbers from six, which is C(6,2), and account for the three combinations per ticket. To ensure all three numbers match, only one ticket is necessary, as it covers the single winning combination of three chosen numbers from the set. The student is attempting to mathematically represent these scenarios but is unsure about the correctness of their formulas. Overall, the discussion focuses on determining the number of tickets needed for different matching criteria in a lottery game.
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Homework Statement


Students are playing a lottery game. In this game, three numbers are drawn from a set of six.

If the three numbers on a student's ticket match those drawn, the student wins the full prize. If just one or two numbers match, the student wins a consolation prize.

The order of the numbers doesn't matter. Also, once a number is picked it cannot be picked again.

a) How many tickets would a student have to buy to guarantee that at least one number out of 3 matches the winning combination?

b) What if at least 2 numbers need to match?

c) What if all 3 numbers need to match?


Homework Equations





The Attempt at a Solution


a) I know that the answer to is 2 tickets. This is because you could buy the following:

1,2,3 on one ticket. 4,5,6 on the other. This way, at least one of the numbers will match the winning ticket.

But I have to represent this mathematically. Would it be (6 choose 1) / 3?

b) If my formula is correct, then it would be (6 choose 2) / 3

c) (6 choose 3) / 3

But I am not sure if my formula is right. I'm having trouble reasoning it out in my head.
 
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It seems fine to me, except the last one. In general, you get the total number of combinations and divide it by the number of winning combinations in each ticket, as a result you get the number of tickets.

For instance, in the 2nd question, we have C(6,2) combinations. However, each ticket has 3 combination (because if we have x,y,z then (x,y), (y,z) and (x,z) are winning combinations). However, in the 3rd question we have C(6,3) but each ticket covers only one winning combination.
 
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