M1 Dynamics: Find Tension, Friction & Force on Pulley

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Two particles, P and Q, are connected by a string over a pulley on a rough inclined plane, with P at rest and Q hanging freely. Upon releasing P, it accelerates up the incline at 2.5 m/s², leading to a calculated tension in the string of 21.9 N and a coefficient of friction of 0.418. The discussion seeks clarification on calculating the force exerted by the string on the pulley, emphasizing the need for understanding the vector difference between tensions on either side of the pulley. There is confusion regarding whether to use vector analysis or Pythagorean theorem for this calculation. The key takeaway is that the force on the pulley can be determined by considering the vector difference of the tensions.
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Two particles P and Q of mass 2 kg and 3 kg respectively are connected by a light inextensible string. The string passes over a small smooth pulley which is fixed at the top of a rough inclined plane. The plane is inclined to the horizontal at an angle of 30°. Particle P is held at rest on the inclined plane and Q hangs freely on the edge of the plane with the string vertical and taut. Particle P is released and it accelerates up the plane at 2.5m s−2. Find

a the tension in the string, I got right T = 21.9

b the coefficient of friction between P and the plane, i got it right too 0.418

c the force exerted by the string on the pulley.

Could someone please go through part c?
And if there is a method/rule for part c on all questions that ask this please let me know!
If it would be around a table so pulley would give 90 degree, and so Pythagoras theorem can be applied but its inclined plane :S Can't understand! and one more thing that in finding the this we have to solve it Vector-ically ? or just Pythagoras theorem? I'm really confused, Pls help! :(
 
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Hi T.S.M! :smile:
T.S.M said:
c the force exerted by the string on the pulley.

It's just the (vector) difference between the tension on either side. :wink:
 
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