1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Maclaurin Series expansion of Lorentz factor

  1. Jun 7, 2009 #1
    1. The problem statement, all variables and given/known data
    Wikipedia states that the Maclaurin Series expansion of the Lorentz factor is http://en.wikipedia.org/wiki/Lorentz_factor" [Broken]

    2. Relevant equations
    Relevant equations are all found in that article

    3. The attempt at a solution

    I don't see how this comes about. My attempt: 1+0+1/2+...

    How can beta be in the expansion, when it should be substituted by 0, since the Maclaurin Series is about 0?
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Jun 7, 2009 #2

    dx

    User Avatar
    Homework Helper
    Gold Member

    The maclaurin series of a function about zero is f(x) = f(0) + f'(0)x + f''(0)x2/2! + ...
     
  4. Jun 7, 2009 #3

    Cyosis

    User Avatar
    Homework Helper

    The Maclaurin series about 0 is given by:

    [tex]\gamma(\beta)=\gamma(0)+\beta \gamma'(0)+\frac{\beta^2}{2!}\gamma''(0)+...[/tex]

    Try it out.
     
  5. Jun 7, 2009 #4
    Yes, thanks. I found my error: I didn't notice the factors (beta) in the terms.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Maclaurin Series expansion of Lorentz factor
Loading...