Magnetic Dipole Moment does not include the permeability of free space?

AI Thread Summary
The magnetic dipole moment does not include the permeability of free space (μ0) because it is defined independently of it. The magnetic dipole moment measures the strength of the interaction between the dipole and an external magnetic field, similar to how the electric dipole moment is defined without including the permittivity of free space (ε0). In practical applications, such as the Stern-Gerlach experiment, the dipole moment influences how particles interact with magnetic fields. The constant μ0 is instead incorporated into the equations for the magnetic field generated by currents. Understanding this distinction clarifies the role of the magnetic dipole moment in magnetic interactions.
H_man
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Magnetic Dipole Moment does not include the permeability of free space?

Hi,

The formula for a magnetic field in a current loop involves the permeability of free space.

But the formula for the magnetic dipole moment which seems to represent the flux through a current loop does not incorporate the permeability of free space.

Whats happening here?

:bugeye:
 
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It's just a question of where you put the constant mu0.
It's not usually put in the mag mom. Then mu0/4pi is put into the Eq. for B, just as it is for B due to currents.
The mag mom is NOT the flux through a current loop.
 
Anything that you measure involving the magnetic moment also involves a magnetics field, and the permeability is included in that magnetic fielc.
 
Thanks for that, though its still not entirely clear.

What exactly is the Magnetic Dipole Moment a measure of then?

I ask this as I know in the Stern Gerlach exp. the Ag atoms experience a torque due to the dipole moments of the electrons being acted upon by the magnetic field into which it enters. And I originally assumed that the dipole moment was a way of stating the magentic field strength of the current loop...



:bugeye:
 
What exactly is the Magnetic Dipole Moment a measure of then?

It is a measure of how strong the interaction between that dipole and an external magnetic field would be.
 
Use the analogue of the electric dipole moment. This is simply the charge times a separation. You do not see \epsilon_0 anywhere, do you ?

Likewise, there is no reason for the magnetic dipole moment to have \mu_0 in it. This is by definition.
 
Last edited:
Thanks guys, its all much clearer now.

:smile:
 

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