Magnetic Field Work: Find Work to Rotate Conductor

AI Thread Summary
The discussion revolves around calculating the work required to rotate a 2-meter conductor carrying a 3 A current in a magnetic field described by cos(ϕ/3) Up Wb/m^2. Participants express confusion over the application of formulas related to torque and magnetic moment, particularly regarding the use of surface area calculations for an elliptical cylinder. There is uncertainty about the meaning of "cos(ϕ/3)Up" in the context of the magnetic field. The initial approach involves using torque to find work, but clarity on the magnetic field's implications is needed. Overall, the thread highlights the complexities of applying physics concepts to solve the problem effectively.
DODGEVIPER13
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Homework Statement


A conductor that is 2 m long and is caring a current of 3 A is placed parallel to the zaxis at a distance ρ0= 10 cm as shown in Figure 2. If the magnetic field in the region is cos(ϕ/3)Up Wb/m^2, how much work is required to rotate the conductor one revolution about the z-axis?

Homework Equations


W=Fd
torque=m x B where m=magnetic moment
m=IS

The Attempt at a Solution


Well I tried formula for surface area of an elliptical cylinder pi(Major radius)(minor radius) which is S but I don't have B. am I going about it wrong? Anyways once I did this I was planning on multiplying it by the current given. And then multiply that by the length of cylinder 2m which will give me the torque force which I can then find the for d=distance traveled in one revolution and multiplt that by the torque to give me work.
 

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Is this a bad question?
 
DODGEVIPER13 said:
Is this a bad question?

Yeah, what does "cos(phi/3)Up mean?
 

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