Magnetic Field Work: Find Work to Rotate Conductor

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SUMMARY

The discussion focuses on calculating the work required to rotate a 2-meter long conductor carrying a 3 A current in a magnetic field described by cos(ϕ/3) Up Wb/m². The key equations involved are W = Fd for work and torque = m x B, where m is the magnetic moment calculated as m = IS. Participants express confusion regarding the magnetic field representation and the correct approach to derive the torque and work needed for one complete revolution about the z-axis.

PREREQUISITES
  • Understanding of magnetic fields and their representations
  • Familiarity with the concepts of torque and magnetic moment
  • Knowledge of the work-energy principle in physics
  • Basic proficiency in calculus for evaluating integrals if necessary
NEXT STEPS
  • Study the derivation of magnetic moment and its application in rotating systems
  • Learn how to interpret and manipulate magnetic field equations like cos(ϕ/3)
  • Explore the relationship between torque, force, and work in rotational dynamics
  • Investigate practical examples of conductors in magnetic fields to solidify understanding
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone involved in electromagnetism or rotational dynamics, particularly those tackling problems related to magnetic fields and conductors.

DODGEVIPER13
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Homework Statement


A conductor that is 2 m long and is caring a current of 3 A is placed parallel to the zaxis at a distance ρ0= 10 cm as shown in Figure 2. If the magnetic field in the region is cos(ϕ/3)Up Wb/m^2, how much work is required to rotate the conductor one revolution about the z-axis?

Homework Equations


W=Fd
torque=m x B where m=magnetic moment
m=IS

The Attempt at a Solution


Well I tried formula for surface area of an elliptical cylinder pi(Major radius)(minor radius) which is S but I don't have B. am I going about it wrong? Anyways once I did this I was planning on multiplying it by the current given. And then multiply that by the length of cylinder 2m which will give me the torque force which I can then find the for d=distance traveled in one revolution and multiplt that by the torque to give me work.
 

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Is this a bad question?
 
DODGEVIPER13 said:
Is this a bad question?

Yeah, what does "cos(phi/3)Up mean?
 

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