Magnetic Fields and the Biot-Savart Law

Click For Summary
SUMMARY

The discussion focuses on the application of the Biot-Savart Law to calculate magnetic fields generated by current-carrying wires. The magnetic field at a distance of 35.0 cm from a straight wire carrying 7.00 A is given as 4.00 µT, with calculations leading to a distance of 466.6667 cm for a field strength of 0.300 µT. Participants also explore the magnetic field produced by two parallel wires carrying equal currents in opposite directions and the magnetic field outside a coaxial cable. Key equations include B = µ0 * I / (2 * π * r), where µ0 is the permeability of free space.

PREREQUISITES
  • Understanding of the Biot-Savart Law
  • Familiarity with magnetic field calculations
  • Knowledge of Ampere's Law
  • Basic algebra for solving equations
NEXT STEPS
  • Study the Biot-Savart Law in detail
  • Learn how to apply Ampere's Law for magnetic field calculations
  • Explore the concept of magnetic field interactions between parallel wires
  • Investigate the properties of coaxial cables and their magnetic fields
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding magnetic fields generated by current-carrying conductors.

DragcoDavid
Messages
1
Reaction score
0
Hi, I'm new here but been looking to you guys for solutions for a while now. However, I cannot find the kind of solution on here already, so I thought I'd put it out here.

My main problem with physics is always just finding the formulas I need. If you can at least point me in the right direction with the right formula(s), I'll be most grateful.

Homework Statement


The magnetic field 35.0 cm away from a long, straight wire carrying current 7.00 A is 4.00 µT.

(a) At what distance is it 0.300 µT?
466.6667 cm

(b) At one instant, the two conductors in a long household extension cord carry equal 7.00 A currents in opposite directions. The two wires are 3.00 mm apart. Find the magnetic field 35.0 cm away from the middle of the straight cord, in the plane of the two wires.

? nT

(c) At what distance is it one tenth as large?

? cm

(d) The center wire in a coaxial cable carries current 7.00 A in one direction, and the sheath around it carries current 7.00 A in the opposite direction. What magnetic field does the cable create at points outside?

? nT

Homework Equations


B= µ0*I / 2*pi*r, where µ0 is 4*pi x 10^-7, I is current in A, and r is distance in meters.

I'm sure there are others, but if I knew them, I'd wouldn't be here.

The Attempt at a Solution



Part A)
B = µ0*I / 2*pi*r
(3e-7 T) = (12.56637e-7)*(7 A) / 2*(3.14159...)*r
r = (12.56637e-7)*(7 A) / 2*(3.14159...)*(3e-7 T) = 14/3 m = 4.6667 m = 466.6667 cm

Part B) ? No idea where to start... I thought the 2 opposite forces would cancel each other out, but not totally it seems. It asks the answer in nano-tesla, so I assume that there is some canceling out here.

Part C) Extension of part B, asking where the field is 1/10th the field is in part B.

Part D) Seems similar to part B, but you tell me.
 
Physics news on Phys.org
Actually, it seems to me as if you are supposed to use Ampere's Law.

b) the cords actually want to push apart, try it out using the right hand rule.

c) plug and chug

d) definitely a question for ampere's law
 

Similar threads

Replies
12
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K