How Does Flipping a Ring Affect Magnetic Flux and Induced EMF?

AI Thread Summary
The discussion focuses on calculating the magnetic flux and induced EMF when flipping a wedding ring in the Earth's magnetic field. The magnetic flux through the ring is determined using the formula involving the magnetic field strength and the area of the ring, resulting in a value of approximately 2.75 x 10^-6 T m². When the ring is flipped 180°, the change in flux is calculated to be about 1.7425 x 10^-8 T m². Using Faraday's law, the induced EMF during the flip is found to be approximately 8.7125 x 10^-8 V. Participants express confusion over the calculations, particularly for parts b and c, seeking further clarification.
ghostbuster25
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The Earth’s magnetic field at a certain location in the UK has a magnitude of 48 μT and is directed at 66° below the horizontal.

a)Determine the magnitude of the flux of the Earth’s magnetic field through a
wedding ring of diameter 2.2 cm when the ring is held in a horizontal plane.

b)What is the magnitude of the flux change when the ring is flipped through 180° about a horizontal axis?

c)Use Faraday’s law to calculate the EMF induced in the ring when it is flipped
through 180° in 0.2 s, assuming the flux changes uniformly during this time.


can anyone help me please i am completely stuck and don't know where to start :(
 
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You would actually probably be better off posting this in introductory physics, but that's okay, let me give you a hand anyway.

a) Remember that the equation for flux is \int \int \mathbf{B}\cdot d\mathbf{a}=\int \int B cos(\phi) da

b) You should have an intuitive guess about this, but go ahead and work it out.

c) Remember that EMF is \frac{d \Phi}{dt}
 
Hi ghostbuster remember the B dot A cross product rule that helped me and the angle is below thw horizontal so work out the angle you need
 
Not all that astonishingly, I have the same homework as ghostbuster. it's getting pretty late now though, but here are my tenuous attempts at the three questions:

a)


Magnetic flux = B dot A; this is the dot product of the B vector and the area vector, A

B = 48 x10^-6 T at 34 degrees from the normal vector to the the area

The A vector has magnitude = the area, and is directed perpendicular to the surface.
Mag A = (2.2 x 10^-2 m)^2

Therefore
flux = (48 x 10^-6 T) (Pi) [(2.2 x 10^-2 m)^2] (cos 34)
= 2.75 x 10^-6 T m ^2

(b)

The A vector changes direction

Δ flux = B A cos (156) – BA cos (34)
= ( -0.9135 - 0.8290) x 10^-8
= 1.7425 x 10^-8 T m2

[c]

Using Faraday's law

EMF = -N
dt

= -1 -1.7425 x 10-8 T m2
0.2 s

= 8.7125 x 10^-8 V

I had some help from a guy, who's reasoning I can't quite follow now he's gone. Part (a) makes most sense to me, but am rather lost with b and c. any help, or hints would be very gratefully recieved
 
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