Magnetic flux density between two wires

Click For Summary
SUMMARY

The discussion focuses on calculating the magnetic flux density at point P between two parallel wires R and S carrying currents of 10 A and 30 A, respectively. The magnetic flux density at point P is determined to be 1.6 x 10-4 T when P is midway between the wires and zero when P is 0.05 m from R and 0.15 m from S. The direction of the magnetic flux density is established using the right-hand rule, indicating that at point P in case (a), the magnetic field points into the paper. In case (b), the opposing magnetic fields from the two wires cancel each other out, resulting in zero magnetic flux density.

PREREQUISITES
  • Understanding of magnetic fields generated by current-carrying wires
  • Familiarity with the right-hand rule for determining magnetic field direction
  • Knowledge of the formula for calculating magnetic flux density, B = μ0 I / (2 π r)
  • Basic concepts of electromagnetism and current direction
NEXT STEPS
  • Study the application of the right-hand rule in various current configurations
  • Learn about the superposition principle in magnetic fields
  • Explore the effects of varying current magnitudes and directions on magnetic flux density
  • Investigate the implications of magnetic flux density in different geometrical arrangements of wires
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in electromagnetism, particularly those studying the behavior of magnetic fields generated by parallel current-carrying wires.

moenste
Messages
711
Reaction score
12

Homework Statement


Two identical wires R and S lie parallel in a horizontal plane, their axes being 0.10 m apart. A current of 10 A flows in R in the opposite direction to a current of 30 A in S. Neglecting the effect of the Earth's magnetic flux density calculate the magnitude and state the direction of the magnetic flux density at a point P in the plane of the wires if P is (a) midway between R and S, (b) 0.05 m from R and 0.15 m from S.

Answers: (a) 1.6 * 10-4 T, (b) zero.

2. The attempt at a solution
(a) 0.1 / 2 = 0.05 m. B = μ0 I / 2 π r = 4 π * 10-7 * 10 / 2 π * 0.05 + 4 π * 10-7 * 30 / 2 π * 0.05 = 1.6 * 10-4 T.

(b) Because the distance between them is 0.1 m and the given distance (0.05 m and 0.15 m) is greater than the 0.1 m, therefore the magnetic flux density at a point P is zero? Not sure on this part.

And how do we determine the direction of the magnetic flux density at P?

5005e3b9da44.jpg


30 - 10 = 20 A, so current at S is stronger so we need to take the P line with our current finger pointing downwards and so the field will be on the left side of P into the paper and on the right side it will be out of paper?
 
Physics news on Phys.org
Everything is correct in a) part. About b) part, that's true that each wire generates magnetic flux in opposite direction so it will cancel, but you got to calculate that just like in a) part. B coming from (lets say) S wire will have + sign and B from R wire will have - sign (depends on orientation of your coordinate system but it doesn't really matter here, what's important is that they have opposite signs). And you determine the direction of magnetic field with ''right hand rule''. Thumb goes in direction of current and 4 other fingers point at the direction of magnetic field.
 
  • Like
Likes   Reactions: moenste
Avalanche_ said:
About b) part, that's true that each wire generates magnetic flux in opposite direction so it will cancel, but you got to calculate that just like in a) part. B coming from (lets say) S wire will have + sign and B from R wire will have - sign (depends on orientation of your coordinate system but it doesn't really matter here, what's important is that they have opposite signs).
Ha, that's indeed so. I actually did calculate it before posting, but I calculated using the calculator right away and summed the numbers and so I missed the fact that they are the same.

I assumed that since the point P is 0.15 m from S so I decided to take it as negative (since it is larger than the 0.1 m distance).

B = 4 * π * 10-7 * 10 / 2 * π * 0.05 - 4 * π * 10-7 * 30 / 2 * π * 0.15 = 4 * 10-5 - 4 * 10-5 = 0 T.

Avalanche_ said:
And you determine the direction of magnetic field with ''right hand rule''. Thumb goes in direction of current and 4 other fingers point at the direction of magnetic field.
Yes, this part I know. You can see it on the image (the circles at the top). I don't know what to do with this part:
moenste said:
state the direction of the magnetic flux density at a point P in the plane of the wires if P is (a) midway between R and S, (b) 0.05 m from R and 0.15 m from S.
As I understand I need to show the direction of B at point P. Point P in (a) is the middle line between the R and S lines. How do I find the direction of B of the P "line"? I mean I don't know it's current, right?

I thought maybe I need to subtract the currents of the S and R lines, like 30 A - 10 A = 20 A so current is facing downwards like the "stronger" wire S... Not sure whether this is correct thinking.
 
Oh, sorry, I didn't see that circles on top of your picture. And about that last part, you already did that. If P is in between wires [ a) part], you calculated the magnetic field, and just look at your circles in between the wires, both pointing in the same direction, so that got to be the direction of magnetic flux density at point P in a) part. And about b) part, you already said it cancels and B=0, so it's not pointing anywhere, it's simply zero, it has no direction at that point.
 
  • Like
Likes   Reactions: moenste
Avalanche_ said:
just look at your circles in between the wires, both pointing in the same direction, so that got to be the direction of magnetic flux density at point P in a) part
Hm, both magnetic fields at P are pointed into the paper (X). So the magnetic field will be into the paper at P?

But if we had a situation when the currents would go in the same direction (not like here in different ones), then the circles would've been into the paper on the left side of the P "line" and on out of the paper on the right side of it. What would we be the magnetic field at P?
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 0 ·
Replies
0
Views
994
Replies
35
Views
6K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 34 ·
2
Replies
34
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
7
Views
2K