Magnetic Force on a Wire with a Changing Direction of Current

AI Thread Summary
The discussion focuses on calculating the magnetic force on a wire segment carrying a current of 62 A, with a magnetic field of 110 mT directed along the z-axis. The wire runs along the x-axis from x=-6m to x=0 and then along the z-axis from z=0 to z=2.9m. Participants clarify that only the segment along the x-axis contributes to the force since it is perpendicular to the magnetic field. The force calculation is simplified to F=ILB, specifically using the length of the wire segment along the x-axis. The final formula proposed for the force is F=6x62x0.11.
Andy111
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Homework Statement


A segment of wire carries a current of 62 A along the x-axis from x=-6m to x=0 and then along the z-axis from z=0 to z=2.9m. The magnetic field is equal to 110 mT in the positive z direction.

What is the magnitude of the force on this segment of wire? Answer in units of N.


Homework Equations



F=ILBsin\theta

F= magnetic force
I= current
L= length of wire
B= magnetic field
sin\theta = the angle

The Attempt at a Solution



First I tried finding the length of the hypotenuse of the wire and the angle, then use the other given variables to solve for F, but I didn't think that was right.
 
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do you really mean that both the wire and the magnetic field is along the z-axis (and not the y-axis)? If both are along the z-axis, no force will will act on that part.
 
I think the only part of the wire that matters is the part that isn't parallel to the magnetic field (ie from -6 to 0 along the x axis, which is perpendicular to the field).
 
Yes, it is the z-axis, not the y.

So is the equation just going to be F=6x62x0.11?
 
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