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I Magnetic levitated electric wire

  1. May 16, 2017 #1
    I'm thinking about making an instrument to show the force on a wire carrying electric current for students in lab. A normal wire which levitates from ground after it has current flowing in it.

    We have the following equations

    F = ILBsin(a)
    W = ALg

    'A' being the mass of unit length of the wire. We will make the magnetic field perpendicular to the current flow so a=Pi/2 and sin(a)=1 and I want the wire to be suspended above the ground so in equilibrium we must have:

    F = W
    ILB = ALg
    IB = Ag

    Since g and A are constant in this device what I will need to do is playing with magnetic field and electric current.
    I'm not very familiar with the Earnshaw theorem but I know if I use an AC current this is doable. I can use normal power outlets (220 V in this case) but I don't know how to create the uniform magnetic field needed. Are natural magnets (Like Neodymium magnets) better or a magnetic field generated by another wire or coil?
    Is there any easier way to do this?
    What are notes to keep in mind in this experiment?
  2. jcsd
  3. May 17, 2017 #2


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