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- Thread starter FA@A
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W = ½∫B·H dV = 1/2μ

where dv is integral over all volume (includuing inside magnets).

The force in the x direction is

F

Bob S

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W = ½∫B·H dV = 1/2μ_{0}∫B^{2}dV

where dv is integral over all volume (includuing inside magnets).

The force in the x direction is

F_{x}= dW/dx

Bob S

I'm not entirely sure that this would work for me. I'm assuming that the 'V' is voltage, but I'm using permanent magnets and this seems like it applies to electromagnets?

- #4

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Voltage does not appear in this situation. The second magnet starts moving when the force exceeds the static friction force. It should be the same if the two magnets repel each other or attract each other. If you put the two magnets on a slope where gravity becomes important, you can measure the actual force by comparing the repulsion force to mg.I'm not entirely sure that this would work for me. I'm assuming that the 'V' is voltage, but I'm using permanent magnets and this seems like it applies to electromagnets?

Bob S

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