How Do You Calculate the Magnitude of a Complex Fractional Vector?

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Homework Statement


Find the magnitude of \frac{6t(-3t^2\hat{i}+\hat{j})}{(1+9t^4)^2}

Homework Equations


The Attempt at a Solution


I know how to take the magnitude for something simple like 3x \hat{i} + 8y \hat{j} + 2 z \hat{k} but not this. My lecture notes don't give me any examples of how to find the magnitude of something in the form of a fraction.
 
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If a and b are real numbers, then what is the magnitude of

a\hat{i} + b\hat{j}?

If you can answer this, then don't let the fraction confuse you - just try to rewrite it in the form

a\hat{i} + b\hat{j}
 
Take the magnitude of the top and the bottom separately and then divide them.
 
Or, use this property of vectors:
||kv|| = |k|||v||

The 6t in the numerator and the denominator are just scalars.
 
All are good suggestions but the thing to realize here is that you might be getting scared of the fraction. What is the magnitude of

{16\hat{i} \over {4}} + {{20\hat{j} \over {4}}?

How is it any different from

{16\hat{i} + {20\hat{j}} \over{4}}?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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