Magnitude of net electric field

Click For Summary
SUMMARY

The discussion centers on calculating the net electric field at the center of a square formed by four point charges, each with a magnitude of 2.2 x 10-12 C. Three charges are positive, and one is negative, positioned at the corners of a square with a side length of 3.0 cm. The formula used for electric field calculation, E = (k|q|)/r2, where k is Coulomb's constant (8.99 x 109 N m2/C2), was initially misapplied. The correct approach involves vector addition of the electric fields due to each charge, considering their directions.

PREREQUISITES
  • Understanding of Coulomb's Law and electric fields
  • Familiarity with vector addition in physics
  • Knowledge of the concept of point charges
  • Basic skills in algebra for calculations
NEXT STEPS
  • Study vector addition of electric fields in electrostatics
  • Learn about the superposition principle in electric fields
  • Explore the effects of charge configuration on electric field strength
  • Investigate the application of electric field calculations in real-world scenarios
USEFUL FOR

Students and professionals in physics, electrical engineering, and anyone interested in understanding electrostatics and electric field calculations.

mayo2kett
Messages
23
Reaction score
0
Four point charges have the same magnitude of 2.2 10-12 C and are fixed to the corners of a square that is 3.0 cm on a side. Three of the charges are positive and one is negative. Determine the magnitude of the net electric field that exists at the center of the square.

i tried using E=(k|q|)/r^2 but it wasn't working and I'm not sure how to combine the electric fields for all of the outside charges...

-annie
 
Physics news on Phys.org
Why doesn't that formula work?
 
this is what i tried ((8.99e9)(2.2e-12))/((3.0e-2)^2) and i got 21.976... so now am i supposed to multiply by 4? cause that answer i got isn't right
-annie
 
Last edited:
ahha i figured it out... :)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
14
Views
2K
Replies
14
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
14
Views
5K
Replies
17
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K