Magnitude of the recoil velocity of the nucleus

In summary, the conversation discusses the decay of the nucleus of 214Po through the emission of an alpha particle with given kinetic energy. The speaker uses the kinetic energy to calculate the velocity of the particle, but is unsure of how to use conservation of momentum to find the recoil velocity of the remaining nucleus. They determine that conservation of momentum applies as there are no external forces, and the initial momentum of the particle is found to be zero. The speaker then questions if there is a known mass for Polonium that can be used in their calculation.
  • #1
ledhead86
59
0
The nucleus of 214Po decays radioactively by emitting an alpha particle (mass 6.65*10^-27) with kinetic energy 1.23*10^-12 J, as measured in the laboratory reference frame.

Assuming that the Po was initially at rest in this frame, find the magnitude of the recoil velocity of the nucleus that remains after the decay.


I used the kinetic energy to solve for the velocity: k=.5mv^2 which is 19233429 m/s. Now I'm not sure what to do with that. I think I'm suppose to use the conservation of momentum theory, but I don't know how.
 
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  • #2
Anyone Know?
 
  • #3
Conservation of momentum theory says that the net momentum stays constant if there are no external forces acting. Are there any external forces? What was the initial momentum?
 
  • #4
No, there are no external forces. Initial momentum= mv= 19233429*6.65*10^-27= 1.27902306*10^-19
 
  • #5
so does conservation of momentum not apply her? What do I need then to find the magnitude of the recoil velocity?
 
  • #6
Before the explosion the particle is at rest. What is its momentum? No external forces means momentum is conserved.
 
  • #7
I have a problem simular to this...

in order to find the recoil velocity... i have tried v=-(sqrt KE*2m)/m ... is there a known mass for Polonium that you plug into this problem? where am i going wrong?
 

1. What is the magnitude of the recoil velocity of the nucleus?

The magnitude of the recoil velocity of the nucleus refers to the speed at which the nucleus moves in the opposite direction after undergoing a nuclear reaction. This velocity is dependent on the mass of the nucleus and the energy released during the reaction.

2. How is the magnitude of the recoil velocity of the nucleus calculated?

The magnitude of the recoil velocity can be calculated using the principle of conservation of momentum. This means that the mass and velocity of the nucleus before the reaction must equal the mass and velocity after the reaction. By solving for the velocity of the nucleus after the reaction, we can determine its magnitude.

3. What factors affect the magnitude of the recoil velocity of the nucleus?

The magnitude of the recoil velocity is affected by the mass of the nucleus, the energy released during the reaction, and the direction of the reaction. A larger nucleus or a more energetic reaction will result in a higher recoil velocity.

4. How does the magnitude of the recoil velocity of the nucleus impact nuclear reactions?

The magnitude of the recoil velocity is an important factor in determining the success of a nuclear reaction. If the velocity is too high, it can cause damage to surrounding particles and structures. Additionally, the direction of the recoil velocity can affect the trajectory of the particles involved in the reaction.

5. Can the magnitude of the recoil velocity of the nucleus be controlled?

Yes, the magnitude of the recoil velocity can be controlled by adjusting the energy and direction of the reaction. Scientists can also use different materials and techniques to help mitigate the effects of the recoil velocity and ensure the success of the nuclear reaction.

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