What is the magnitude and direction of vector C?

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To find the magnitude of vector C, calculated as C = 2a - b, where a = 12i + 16j and b = -24 + 10j, the resulting magnitude is confirmed to be 64. For the second question, with vector C having a magnitude of 2.5 cm at 80 degrees and vector D at 3.5 cm at 120 degrees, the direction of vector E, calculated as E = D - 2C, requires understanding the relationship between vector components and angles. The discussion emphasizes the importance of using the correct formulas, such as the square root of (Ax)^2 + (Ay)^2 for magnitude and the arctangent function for angle calculations. The conversation highlights the need for clarity in vector calculations and the relationships between horizontal and vertical components.
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I need help with the following questions-

1. if a= 12i+16j and b=-24+10j, what is the magnitude of the vector C=2a-b?


2.If the magnitude and direction of c are 2.5 cm and 80degree , and d[3.5cm,120degree] and e=d-2c then what is the direction of e, (to the nearest degree)?
 
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1. What information can you use in order to find the magnitude of a vector?
 
you can use any formulas..
 
So which one would YOU pick? :smile:
 
I would use square root of (Ax)^2+ (Ay)^2
 
Indeed, smart choice!

So, what info are you at present lacking in order to calculate the magnitude?

And:
How can you OBTAIN that necessary information?
 
no i got my answer as 64, just want to verify that, and I dnt have no clue about the second question
 
Well, I don't bother to calculate myself all the way to 64 or to any other dumb number, I want to find out:
HOW did you are at whatever number you got?
 
can u help me with my second question
 
  • #10
The degrees are measured with respect to the positive x-axis.
So:
How can that help you?
 
  • #11
well i really don't know
 
  • #12
Well, how har the horizontal&vertical components of a vector related to the vector's magnitude and the angle the vector makes with the positive x-axis?
 
  • #13
i think it get calcuate arc tan of Ax/Ay
 
  • #14
No!
Go back to your book, and read your definitions again.
 
  • #15
rasikan said:
i think it get calcuate arc tan of Ax/Ay

Check it for some special cases...
What angle do you expect? and What do you get with your formula?
- for a vector along the x-axis.
- for a vector along the y-axis.
 
  • #16
Moved from Advanced Physics to Intro Physics.
 
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