Mappings and Inverses: More Than One Left Inverse?

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A mapping can have multiple left inverses if it is not surjective, meaning not every element in the codomain is mapped from the domain. This occurs because different elements in the codomain can correspond to the same element in the domain, allowing for multiple left inverses. The initial confusion arises from the definition of a mapping, which states that each element in the domain maps to one element in the codomain, but does not restrict the codomain elements from having multiple pre-images. The discussion clarifies that these different left inverses correspond to codomain values that lack a unique inverse due to the mapping's non-surjectivity. Understanding this concept resolves the apparent contradiction regarding mappings and their inverses.
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Hi,
just re-reading my lecture notes and there's a bit where it says

"The same mapping may have more than one left inverse (if it is not surjective) and more than one right inverse (if it is not injective)."

I can see how a mapping could have more than one right inverse. But how could it have more than one left inverse? This implies that you have one element from the domain being mapped to two different elements in the codomain. But my definition of a map is

"If A and B are sets then a mapping from A to B is a rule which associates to each element of A one and only one element of B".

Surely this is a contradiction?

Thanks for your help.
 
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The different left inverses are for different values of the elements in the codomain that don't have inverse because f is not onto.
 
Ah i see. Thanks!
 
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