MHB Margin of error and point estimate together

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In a confidence interval of [5.9, 8.1], the point estimate is calculated as the mean, which is 7.0. The margin of error represents the deviation from this mean, calculated as 1.1. To find the margin of error, subtract the mean from the upper endpoint, 8.1, resulting in 1.1. The confidence interval can be expressed as 7.0 ± 1.1. Understanding these calculations is essential for accurate statistical analysis.
aprilryan
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Hey all I have one last question for you. I just need clarification on point estimate and margin of error as I have to find both in a problem. Let's say the endpoints are 5.9 and 8.1. When I do a margin of error problem, I subtract the mean of 7 from 8.1 right? When I do point estimate do I add or subtract 8.1 from 5.9 or the margin of error?

Thanks! Hope you all have a great summer!
 
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aprilryan said:
Hey all I have one last question for you. I just need clarification on point estimate and margin of error as I have to find both in a problem. Let's say the endpoints are 5.9 and 8.1. When I do a margin of error problem, I subtract the mean of 7 from 8.1 right? When I do point estimate do I add or subtract 8.1 from 5.9 or the margin of error?

Thanks! Hope you all have a great summer!

Hi aprilryan!

With a confidence interval of [5.9, 8.1], the point estimate is the mean, which is 7.0.
The margin of error is how much the confidence interval can deviate from 7, which is 1.1.
We can also write the confidence interval as $7.0 \pm 1.1$.

Cheers! ;)
 

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