Marion and thornton classical dynamics

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Discussion Overview

The discussion revolves around potential errors in the equations presented in Marion and Thornton's "Classical Dynamics" and Goldstein's "Classical Mechanics." Participants are examining specific equations related to the motion of free-falling objects, particularly in the context of Coriolis effects and the initial conditions required for integration.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant questions the derivation of an initial condition required for integrating an equation related to the motion of a free-falling object.
  • Another participant clarifies that the equation in question describes the eastward Coriolis deflection of a free-falling object in the Northern Hemisphere.
  • A participant discusses the trajectory of an object dropped from height, suggesting it follows a ballistic trajectory influenced by the Earth's rotation, leading to a deflection eastward of the launch point.
  • Further elaboration is provided on the behavior of an object projected upward, explaining that it will land westward of its launch coordinates due to changes in angular velocity during its ascent and descent.
  • A Java applet is mentioned as a resource for exploring the discussed scenarios, although its relevance is not universally acknowledged.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the initial conditions and the implications of the equations discussed. There is no consensus on the interpretation of the equations or the conclusions drawn about the trajectories of the objects.

Contextual Notes

Participants note the neglect of air friction in their discussions, which may affect the accuracy of the trajectories described. The discussion also highlights the dependence on specific conditions and assumptions related to the motion of objects in a rotating reference frame.

ehrenfest
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Hello,

Does anyone have marion and thornton's classical dynamics book? I have a possible error that I wanted to point out. Actually, goldstein's classical mechanics book would work also since I found the same "error" in there as well.
 
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I have the second edition of goldstein's book. Why don't you just ask your question here, and those who have the book/s will be able to help.
 
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ehrenfest said:
Hello,

Does anyone have marion and thornton's classical dynamics book? I have a possible error that I wanted to point out. Actually, goldstein's classical mechanics book would work also since I found the same "error" in there as well.

I have both books, but not in their latest editions. I might not be able to look at them until tomorrow.

What error do these books have in common?
 
OK. I am pretty sure this is not an not an error now that I found it in both books.

equation 4.93 in goldstein:

m\frac{d^2x}{dt^2}=-2m\omega v_z \sin \theta

They show that

v_z = -gt

So the first equation becomes m\frac{d^2x}{dt^2}= 2m\omega gt \sin \theta

What I DO NOT understand is how they integrate that twice to obtain

x = \omega g t^3 \sin \theta /3

To do that, they need the initial condition \frac{dx}{dt}(t=0) = 0. I do not understand how they get that initial condition!

Also, in a footnote of Goldstein, they say "It is easy to show, using Eq (4.93), that a particle projected upward will fall back to the ground westward of its original launching spot." That is extremely confusing to me.
 
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ehrenfest said:
OK. I am pretty sure this is not an not an error now that I found it in both books.

equation 4.93 in goldstein:

m\frac{d^2x}{dt^2}=-2m\omega v_z \sin \theta

They show that

v_z = -gt

So the first equation becomes m\frac{d^2x}{dt^2}= 2m\omega gt \sin \theta

What I DO NOT understand is how they integrate that twice to obtain

x = \omega g t^3 \sin \theta /3

To do that, they need the initial condition \frac{dx}{dt}(t=0) = 0. I do not understand how they get that initial condition!

Also, in a footnote of Goldstein, they say "It is easy to show, using Eq (4.93), that a particle projected upward will fall back to the ground westward of its original launching spot." That is extremely confusing to me.
Could you be more specific? In what context is the above equation derived?
 
x is the eastward coriolis deflection of a free-falling object in the Northern Hemisphere
 
ehrenfest said:
x is the eastward coriolis deflection of a free-falling object in the Northern Hemisphere
What is the initial velocity of the free-falling body?
 
zero
 
ehrenfest said:
Also, in a footnote of Goldstein, they say "It is easy to show, using Eq (4.93), that a particle projected upward will fall back to the ground westward of its original launching spot." That is extremely confusing to me.

Let me first discuss what is happening when an object is dropped from height.
(In all of the following discussion I'm neglecting air friction.)

The trajectory of an object that is released from altitude is a ballistic trajectory. It has an initial tangential velocity, from co-rotating with the Earth. You can think of the starting point of the trajectory as the apogee of an eccentric orbit.

On its way down from apogee the angular velocity of the object in orbit increases. (Compare the extremely eccentric orbit of Halley's comet; falling towards the Sun it speeds up.)

That is why an object released from altitude will not fall perpendicular to the ground, it will reach the surface eastward of its launch coordinates.Now the case of an object fired upward.
That trajectory is like that of an orbiting object moving upward to its apogee.
In climbing up the object loses angular velocity. So relative to the Earth the object will "fall behind". Later, during the descent, it will get that angular velocity back, but in the meantime the Earth has turned underneath all that.
Therefore an object fired straight up will land westward of the coordinates that it has been launched from.

There's a Java applet on my website designed for exploring precisely that kind of scenario: http://www.cleonis.nl/physics/ejs/ballistics_and_orbits_simulation.php"

Cleonis
http://www.cleonis.nl
 
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